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Two pipes A and B can fill a tank in 10 hours and 15 hours respectively while a third pipe C can empty the full tank in 20 hours. All the pipes are opened for 5 hours and then C is closed. Find the time in which the tank is full?
  • a)
    5.5 hrs
  • b)
    6.5 hrs
  • c)
    7.5 hrs
  • d)
    8.5 hrs
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?
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Two pipes A and B can fill a tank in 10 hours and 15 hours respectivel...
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Two pipes A and B can fill a tank in 10 hours and 15 hours respectivel...
Given:
Pipe A can fill the tank in 10 hours
Pipe B can fill the tank in 15 hours
Pipe C can empty the tank in 20 hours
All pipes are opened for 5 hours and then C is closed.

Approach:
Let the capacity of the tank be 'x'.
In 1 hour, pipe A can fill x/10 part of the tank.
In 1 hour, pipe B can fill x/15 part of the tank.
In 1 hour, pipe C can empty x/20 part of the tank.

Let us assume that the tank is filled in 't' hours.

After 5 hours, the fraction of the tank filled by pipes A and B is (5/x) * [(x/10) + (x/15)] = (1/6).
So, the remaining fraction of the tank to be filled is (1 - 1/6) = (5/6).

Now, only pipes A and B are working.
So, the fraction of the tank filled by pipes A and B in 't-5' hours is (5/6).
[(t-5)/10] * (x/10) + [(t-5)/15] * (x/15) = (5/6)

Solving the above equation, we get t = 7.5 hours.

Therefore, the tank will be full in 7.5 hours.

Answer: Option C.
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Community Answer
Two pipes A and B can fill a tank in 10 hours and 15 hours respectivel...
(1/10 + 1/15 – 1/20)*5 + (1/10 + 1/15)*T = 1. We will get T = 2.5 hrs
so total time = 5 + 2.5 = 7.5 hrs
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Two pipes A and B can fill a tank in 10 hours and 15 hours respectively while a third pipe C can empty the full tank in 20 hours. All the pipes are opened for 5 hours and then C is closed. Find the time in which the tank is full?a)5.5 hrsb)6.5 hrsc)7.5 hrsd)8.5 hrse)None of theseCorrect answer is option 'C'. Can you explain this answer?
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