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It is required to connect a transducer having an open-circuit voltage of 1 V and a source resistance of 1 MΩ to a load of 1-kΩ resistance. Find the load voltage if the connection is done
- a)1 μV and 1 mV respectively
- b)1 mV and 1 V respectively
- c)0.1 μV and 0.1 mV respectively
- d)0.1 mV and 0.1 V respectively
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
It is required to connect a transducer having an open-circuit voltage ...
When a unity gain follower is uses then input signal is equal to output signal. When connected directly, output signal is given by 1 X 1kΩ/1MΩ or 1mV.
Most Upvoted Answer
It is required to connect a transducer having an open-circuit voltage ...
Ω to a load resistance of 1 kΩ. To do this, we can use a voltage divider circuit.
A voltage divider circuit consists of two resistors connected in series. The input voltage is connected across the resistor with the higher resistance, and the output voltage is taken across the resistor with the lower resistance.
In this case, the transducer with an open-circuit voltage of 1 V can be considered as the input voltage. We want to connect it to a load resistance of 1 kΩ.
To calculate the resistor values for the voltage divider circuit, we can use the formula:
Vout = Vin * (R2 / (R1 + R2))
Where:
Vout is the output voltage across R2
Vin is the input voltage (1 V)
R1 is the resistance connected to Vin (1 MΩ)
R2 is the resistance connected to Vout (1 kΩ)
Substituting the given values into the formula, we can solve for R2:
Vout = 1 * (R2 / (1M + R2))
Vout = R2 / (1M + R2)
Vout * (1M + R2) = R2
Vout * 1M + Vout * R2 = R2
Vout * 1M = R2 - Vout * R2
Vout * 1M = R2 * (1 - Vout)
R2 = (Vout * 1M) / (1 - Vout)
Since we want Vout to be equal to 1 V (the input voltage), we can substitute Vout = 1 into the equation:
R2 = (1 * 1M) / (1 - 1)
R2 = 1M
Therefore, the value of the resistor R2 should be 1 MΩ.
A voltage divider circuit consists of two resistors connected in series. The input voltage is connected across the resistor with the higher resistance, and the output voltage is taken across the resistor with the lower resistance.
In this case, the transducer with an open-circuit voltage of 1 V can be considered as the input voltage. We want to connect it to a load resistance of 1 kΩ.
To calculate the resistor values for the voltage divider circuit, we can use the formula:
Vout = Vin * (R2 / (R1 + R2))
Where:
Vout is the output voltage across R2
Vin is the input voltage (1 V)
R1 is the resistance connected to Vin (1 MΩ)
R2 is the resistance connected to Vout (1 kΩ)
Substituting the given values into the formula, we can solve for R2:
Vout = 1 * (R2 / (1M + R2))
Vout = R2 / (1M + R2)
Vout * (1M + R2) = R2
Vout * 1M + Vout * R2 = R2
Vout * 1M = R2 - Vout * R2
Vout * 1M = R2 * (1 - Vout)
R2 = (Vout * 1M) / (1 - Vout)
Since we want Vout to be equal to 1 V (the input voltage), we can substitute Vout = 1 into the equation:
R2 = (1 * 1M) / (1 - 1)
R2 = 1M
Therefore, the value of the resistor R2 should be 1 MΩ.
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It is required to connect a transducer having an open-circuit voltage of 1 V and a source resistance of 1 MΩ to a load of 1-kΩ resistance. Find the load voltage if the connection is donea)1 μV and 1 mV respectivelyb)1 mV and 1 V respectivelyc)0.1 μV and 0.1 mV respectivelyd)0.1 mV and 0.1 V respectivelyCorrect answer is option 'B'. Can you explain this answer?
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