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A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.
- a)-30mV/mA and 120mV/mA respectively
- b)30mV/mA and 60mV/mA respectively
- c)-60mV/mA and +60mV/mA respectively
- d)-30mV/mA and -120mV/mA respectively
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A designer requires a shunt regulator of approximately 20 V. Two kinds...
Ω, and 12-V devices with rz of 20 Ω. Which Zener diode should the designer choose for the application?
To determine which Zener diode to choose, we need to calculate the power dissipation for each option and choose the one with the lowest power dissipation.
For the 6.8-V Zener diode:
Vz = 6.8 V
r_z = 10 Ω
I_z = Vz / r_z = 6.8 V / 10 Ω = 0.68 A
P_diss = Vz * I_z = 6.8 V * 0.68 A = 4.624 W
For the 12-V Zener diode:
Vz = 12 V
r_z = 20 Ω
I_z = Vz / r_z = 12 V / 20 Ω = 0.6 A
P_diss = Vz * I_z = 12 V * 0.6 A = 7.2 W
Based on the power dissipation calculations, the 6.8-V Zener diode would be a better choice for the application as it has a lower power dissipation of 4.624 W compared to the 12-V Zener diode's power dissipation of 7.2 W.
To determine which Zener diode to choose, we need to calculate the power dissipation for each option and choose the one with the lowest power dissipation.
For the 6.8-V Zener diode:
Vz = 6.8 V
r_z = 10 Ω
I_z = Vz / r_z = 6.8 V / 10 Ω = 0.68 A
P_diss = Vz * I_z = 6.8 V * 0.68 A = 4.624 W
For the 12-V Zener diode:
Vz = 12 V
r_z = 20 Ω
I_z = Vz / r_z = 12 V / 20 Ω = 0.6 A
P_diss = Vz * I_z = 12 V * 0.6 A = 7.2 W
Based on the power dissipation calculations, the 6.8-V Zener diode would be a better choice for the application as it has a lower power dissipation of 4.624 W compared to the 12-V Zener diode's power dissipation of 7.2 W.
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Community Answer
A designer requires a shunt regulator of approximately 20 V. Two kinds...
Three 6.8v zeners provide 3 x 6.8 = 20.4v with 3 x 10 =30Ω Resistance, neglecting R, we have
load Regulation = -30mV/mA.
For 5.1 Zeners we need 4 diodes to provide 20.4v with 4 x 30 =120Ω Resistance.
load Regulation = -120mV/mA .
load Regulation = -30mV/mA.
For 5.1 Zeners we need 4 diodes to provide 20.4v with 4 x 30 =120Ω Resistance.
load Regulation = -120mV/mA .
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A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer?
Question Description
A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer?.
A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer?.
Solutions for A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
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A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A designer requires a shunt regulator of approximately 20 V. Two kinds of Zener diodes are available: 6.8-V devices with rz of 10 Ω and 5.1-V devices with rz of 30 Ω. For the two major choices possible, find the load regulation. In this calculation neglect the effect of the regulator resistance R.a)-30mV/mA and 120mV/mA respectivelyb)30mV/mA and 60mV/mA respectivelyc)-60mV/mA and +60mV/mA respectivelyd)-30mV/mA and -120mV/mA respectivelyCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
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