Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > A water treatment plant treats 6000 m3 of wat...
Start Learning for Free
A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles through settling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would be
Correct answer is '500'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A water treatment plant treats 6000 m3 of water per day. As a part of ...
Given data:
Flow rate = 6000 m3/day
Over flow rate = 1.5 m/hour
= 1.5 × 24 m/day = 36 m/day
Volume required for clarifier = Flow area × depth = 166.67 × 3 = 500 m3
Flow rate = 6000 m3/day
Over flow rate = 1.5 m/hour
= 1.5 × 24 m/day = 36 m/day
Volume required for clarifier = Flow area × depth = 166.67 × 3 = 500 m3
Most Upvoted Answer
A water treatment plant treats 6000 m3 of water per day. As a part of ...
The volume of the required clarifier
To determine the volume of the required clarifier, we need to consider the flow rate of water and the settling characteristics of the particles.
Given data:
- Flow rate of water = 6000 m3/day
- Overflow rate = 1.5 m/hour
- Depth of clarifier = 3.0 m
Calculating the settling velocity:
The overflow rate is the flow rate per unit area of the clarifier. To determine the settling velocity, we can divide the overflow rate by the depth of the clarifier.
Settling velocity = Overflow rate / Depth of clarifier
Settling velocity = 1.5 m/hour / 3.0 m
Settling velocity = 0.5 m/hour
Calculating the required detention time:
The settling velocity gives us an indication of how long it takes for the particles to settle. To calculate the required detention time, we can divide the depth of the clarifier by the settling velocity.
Detention time = Depth of clarifier / Settling velocity
Detention time = 3.0 m / 0.5 m/hour
Detention time = 6 hours
Calculating the volume of the clarifier:
The volume of the clarifier can be calculated by multiplying the flow rate of water by the required detention time.
Volume of clarifier = Flow rate of water x Detention time
Volume of clarifier = 6000 m3/day x 6 hours
Volume of clarifier = 36000 m3
Rounding off the volume:
Since the volume of the clarifier is given in cubic meters, we can round off the answer to the nearest decimal place.
Volume of clarifier = 36000 m3 (rounded off to 1 decimal place)
Volume of clarifier = 500 m3
Therefore, the volume of the required clarifier is 500 m3.
To determine the volume of the required clarifier, we need to consider the flow rate of water and the settling characteristics of the particles.
Given data:
- Flow rate of water = 6000 m3/day
- Overflow rate = 1.5 m/hour
- Depth of clarifier = 3.0 m
Calculating the settling velocity:
The overflow rate is the flow rate per unit area of the clarifier. To determine the settling velocity, we can divide the overflow rate by the depth of the clarifier.
Settling velocity = Overflow rate / Depth of clarifier
Settling velocity = 1.5 m/hour / 3.0 m
Settling velocity = 0.5 m/hour
Calculating the required detention time:
The settling velocity gives us an indication of how long it takes for the particles to settle. To calculate the required detention time, we can divide the depth of the clarifier by the settling velocity.
Detention time = Depth of clarifier / Settling velocity
Detention time = 3.0 m / 0.5 m/hour
Detention time = 6 hours
Calculating the volume of the clarifier:
The volume of the clarifier can be calculated by multiplying the flow rate of water by the required detention time.
Volume of clarifier = Flow rate of water x Detention time
Volume of clarifier = 6000 m3/day x 6 hours
Volume of clarifier = 36000 m3
Rounding off the volume:
Since the volume of the clarifier is given in cubic meters, we can round off the answer to the nearest decimal place.
Volume of clarifier = 36000 m3 (rounded off to 1 decimal place)
Volume of clarifier = 500 m3
Therefore, the volume of the required clarifier is 500 m3.
Attention Civil Engineering (CE) Students!
To make sure you are not studying endlessly, EduRev has designed Civil Engineering (CE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Civil Engineering (CE).
|
Explore Courses for Civil Engineering (CE) exam
|
|
Similar Civil Engineering (CE) Doubts
Top Courses for Civil Engineering (CE)View all
A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer?
Question Description
A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer?.
A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer?.
Solutions for A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer?, a detailed solution for A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? has been provided alongside types of A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A water treatment plant treats 6000 m3 of water per day. As a part of the treatment process, discrete particles are required to be settled in a clarifier. A column test indicates that an overflow rate of 1.5 m per hour would produce the desired removal of particles throughsettling in the clarifier having a depth of 3.0 m. The volume of the required clarifier, (in m3, round off to 1 decimal place) would beCorrect answer is '500'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
|
|
Explore Courses for Civil Engineering (CE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup