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A refrigerator is such that it extracts 20kJ of heat at a lower temperature and give out 50kJ of heat to the surrounding, what is the coefficient of performance (K)
    Correct answer is '0.67'. Can you explain this answer?
    Verified Answer
    A refrigerator is such that it extracts 20kJ of heat at a lower temper...

    W = QK – QL

    = 20/30
    K = 0.67
    The correct answer is: 0.67
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    Most Upvoted Answer
    A refrigerator is such that it extracts 20kJ of heat at a lower temper...
    Explanation:

    The coefficient of performance (K) of a refrigerator is a measure of its efficiency and is defined as the ratio of the heat extracted from the refrigerator to the work done on the refrigerator.

    K = Qc / W

    where K is the coefficient of performance, Qc is the heat extracted from the refrigerator, and W is the work done on the refrigerator.

    In this case, the refrigerator extracts 20 kJ of heat at a lower temperature and gives out 50 kJ of heat to the surroundings.

    Heat extracted from the refrigerator (Qc) = 20 kJ
    Heat given out to the surroundings (Qh) = 50 kJ

    We can calculate the work done on the refrigerator using the first law of thermodynamics, which states that the work done on a system is equal to the heat added to the system minus the heat extracted from the system.

    W = Qh - Qc

    Substituting the values, we get:

    W = 50 kJ - 20 kJ = 30 kJ

    Now, we can calculate the coefficient of performance (K) using the formula:

    K = Qc / W

    Substituting the values, we get:

    K = 20 kJ / 30 kJ = 0.67

    Therefore, the coefficient of performance (K) of the refrigerator is 0.67.
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    A refrigerator is such that it extracts 20kJ of heat at a lower temperature and give out 50kJ of heat to the surrounding, what is the coefficient of performance (K)Correct answer is '0.67'. Can you explain this answer?
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