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A and B start working together on a project and both have the same efficiency in the beginning. However the efficiency of A decreases to 0.6 times the usual after working for 2 hours. If the project can be finished in 120 man hours, then find the minimum number of days required to finish the work if both do an equal manhours of work each day and the sum of the total number of hours of work by both each day is 12. [ Initial efficiency of A = Efficiency of B = 1 man hour].
  • a)
    10 days
  • b)
    12 days
  • c)
    16 days
  • d)
    Cannot be determined
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A and B start working together on a project and both have the same eff...
Let the number of hours worked by B be x.
The hours worked by A = (12 - x)
The manhours of work finished by A = (12 - x - 2) x 0.6 + 2
(12 - x - 2) x 0.6 + 2 = x
x = 5
The total manhours o f work done by them in a day = 2*x = 2 x 5 = 10
Thus, the number of days required to finsih the work = 120/10 =12 days
Hence, option 2.
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Most Upvoted Answer
A and B start working together on a project and both have the same eff...
Given Information:
- A and B start working together on a project with the same efficiency initially.
- After working for 2 hours, the efficiency of A decreases to 0.6 times the usual efficiency.
- The project can be finished in 120 man hours.
- Both A and B do an equal number of man hours of work each day.
- The sum of the total number of hours of work by both each day is 12.

Approach:
To find the minimum number of days required to finish the work, we need to calculate the number of man hours each day until the project is completed. Since both A and B have the same efficiency initially, we can assume that they each work for 6 hours every day.

Calculation:
Let's assume that A and B each work for 6 hours every day until the project is completed. Since the sum of the total number of hours of work by both each day is 12, this means that they will complete 2 days of work in a single day.

After working for 2 hours, the efficiency of A decreases to 0.6 times the usual efficiency. This means that A will complete 0.6 * 6 = 3.6 hours of work in the next 2 hours.

Therefore, in a single day, A will complete 6 hours of work initially and an additional 3.6 hours of work after the first 2 hours. This totals to 6 + 3.6 = 9.6 hours of work in a single day.

Since A and B complete 2 days of work in a single day, the total number of days required to complete the project is 120 / 9.6 = 12.5 days.

Since the question asks for the minimum number of days required to finish the work, we can round up the value to the nearest whole number.

Therefore, the minimum number of days required to finish the work is 13 days.

Conclusion:
The minimum number of days required to finish the work if both A and B do an equal number of man hours of work each day and the sum of the total number of hours of work by both each day is 12 is 13 days. Therefore, the correct answer is option (B) 12 days.
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A and B start working together on a project and both have the same efficiency in the beginning. However the efficiency of A decreases to 0.6 times the usual after working for 2 hours. If the project can be finished in 120 man hours, then find the minimum number of days required to finish the work if both do an equal manhours of work each day and the sum of the total number of hours of work by both each day is 12. [ Initial efficiency of A = Efficiency of B = 1 man hour].a)10 daysb)12 daysc)16 daysd)Cannot be determinedCorrect answer is option 'B'. Can you explain this answer?
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