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The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:
[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 m
Gravitational acceleration on Earth = 10 ms–2]
  • a)
    650 K
  • b)
    104 K
  • c)
    3 X 105 K
  • d)
    800 K
Correct answer is option 'B'. Can you explain this answer?
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The temperature, at which the root mean square velocity of hydrogen mo...
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The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer?
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The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer?.
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