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The roots of a quadratic equation x2−4px+4p2−q2=0 are
  • a)
    p + 2q, p – 2q
  • b)
    2p + q, 2p – q
  • c)
    2p + q, 2p + q
  • d)
    2p – q, 2p – q
Correct answer is option 'B'. Can you explain this answer?
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The roots of a quadratic equationx2−4px+4p2−q2=0area)p + 2...
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The roots of a quadratic equationx2−4px+4p2−q2=0area)p + 2...
The roots of a quadratic equation can be found using the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.

The discriminant, b^2 - 4ac, determines the nature of the roots:

- If the discriminant is positive, then there are two real roots.
- If the discriminant is zero, then there is one real root (which is also called a double root).
- If the discriminant is negative, then there are two complex roots (which are conjugates of each other).

For example, consider the quadratic equation x^2 + 4x + 4 = 0. Here, a = 1, b = 4, and c = 4. Plugging these values into the quadratic formula gives:

x = (-4 ± √(4^2 - 4(1)(4))) / 2(1)
x = (-4 ± 0) / 2
x = -2

So the equation has one real root, x = -2.
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The roots of a quadratic equationx2−4px+4p2−q2=0area)p + 2q, p – 2qb)2p + q, 2p – qc)2p + q, 2p + qd)2p – q, 2p – qCorrect answer is option 'B'. Can you explain this answer?
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