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The taxi fare in a city is as follows For the first km , the fare is rupees 50 , for distance it is 20 rupees per km. Taking distance as x km and the total fare as rupees y write a linear equation.?
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The taxi fare in a city is as follows For the first km , the fare is r...
Linear Equation for Taxi Fare
The taxi fare in the city can be represented by a linear equation. The equation will have two variables, distance, and the total fare. Let's assume that the distance traveled by the passenger is x km and the total fare charged by the taxi driver is y rupees.
Fare for the first km
For the first km, the fare charged by the taxi driver is 50 rupees. This is a fixed amount, which means that no matter how much distance the passenger travels, the first km's fare will remain the same.
Fare for the remaining distance
After the first km, the fare charged by the taxi driver is 20 rupees per km. This means that for every km traveled after the first km, the fare will be 20 rupees.
Writing the Linear Equation
To write the linear equation for taxi fare, we need to consider both the fixed cost and the variable cost. The fixed cost is 50 rupees, and the variable cost is 20 rupees per km.
The linear equation for taxi fare can be written as:
y = 50 + 20x
Here, y represents the total fare charged by the taxi driver, and x represents the distance traveled by the passenger.
Explanation of the Linear Equation
The equation y = 50 + 20x represents a straight line on a graph, with y-intercept as 50 and slope as 20. The y-intercept represents the fixed cost, which is 50 rupees, and the slope represents the variable cost, which is 20 rupees per km.
The equation can be used to calculate the total fare charged by the taxi driver for any distance traveled by the passenger. For example, if the passenger travels a distance of 6 km, the total fare charged by the taxi driver will be:
y = 50 + 20(6)
y = 50 + 120
y = 170
Therefore, the total fare charged by the taxi driver for a distance of 6 km will be 170 rupees.
The taxi fare in the city can be represented by a linear equation. The equation will have two variables, distance, and the total fare. Let's assume that the distance traveled by the passenger is x km and the total fare charged by the taxi driver is y rupees.
Fare for the first km
For the first km, the fare charged by the taxi driver is 50 rupees. This is a fixed amount, which means that no matter how much distance the passenger travels, the first km's fare will remain the same.
Fare for the remaining distance
After the first km, the fare charged by the taxi driver is 20 rupees per km. This means that for every km traveled after the first km, the fare will be 20 rupees.
Writing the Linear Equation
To write the linear equation for taxi fare, we need to consider both the fixed cost and the variable cost. The fixed cost is 50 rupees, and the variable cost is 20 rupees per km.
The linear equation for taxi fare can be written as:
y = 50 + 20x
Here, y represents the total fare charged by the taxi driver, and x represents the distance traveled by the passenger.
Explanation of the Linear Equation
The equation y = 50 + 20x represents a straight line on a graph, with y-intercept as 50 and slope as 20. The y-intercept represents the fixed cost, which is 50 rupees, and the slope represents the variable cost, which is 20 rupees per km.
The equation can be used to calculate the total fare charged by the taxi driver for any distance traveled by the passenger. For example, if the passenger travels a distance of 6 km, the total fare charged by the taxi driver will be:
y = 50 + 20(6)
y = 50 + 120
y = 170
Therefore, the total fare charged by the taxi driver for a distance of 6 km will be 170 rupees.
Community Answer
The taxi fare in a city is as follows For the first km , the fare is r...
Taxi fair for 1rst km=8rs
total fare after first km=5rs
total distance=X
total fare=y
equation:
y=(x-1)+8
find value ok by 1rst X=0and y=0
total fare after first km=5rs
total distance=X
total fare=y
equation:
y=(x-1)+8
find value ok by 1rst X=0and y=0
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The taxi fare in a city is as follows For the first km , the fare is rupees 50 , for distance it is 20 rupees per km. Taking distance as x km and the total fare as rupees y write a linear equation.?
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The taxi fare in a city is as follows For the first km , the fare is rupees 50 , for distance it is 20 rupees per km. Taking distance as x km and the total fare as rupees y write a linear equation.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The taxi fare in a city is as follows For the first km , the fare is rupees 50 , for distance it is 20 rupees per km. Taking distance as x km and the total fare as rupees y write a linear equation.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The taxi fare in a city is as follows For the first km , the fare is rupees 50 , for distance it is 20 rupees per km. Taking distance as x km and the total fare as rupees y write a linear equation.?.
The taxi fare in a city is as follows For the first km , the fare is rupees 50 , for distance it is 20 rupees per km. Taking distance as x km and the total fare as rupees y write a linear equation.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The taxi fare in a city is as follows For the first km , the fare is rupees 50 , for distance it is 20 rupees per km. Taking distance as x km and the total fare as rupees y write a linear equation.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The taxi fare in a city is as follows For the first km , the fare is rupees 50 , for distance it is 20 rupees per km. Taking distance as x km and the total fare as rupees y write a linear equation.?.
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