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The taxi fare in the city is as follows : for the first kilometer,the fare is rupees 8 and for the subsequent distance it is rupees 5 per KM . Taking the distance covered as x km and toal fare as rupees y, write a linear equation for this information , and draw its graph.?
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The taxi fare in the city is as follows : for the first kilometer,the ...
**Linear Equation for Taxi Fare**
The taxi fare in the city is given as follows:
- For the first kilometer, the fare is rupees 8.
- For the subsequent distance, it is rupees 5 per KM.
Let's take the distance covered as x km and the total fare as rupees y. To find the linear equation for this information, we need to use the concept of slope-intercept form of a linear equation.
The slope-intercept form of a linear equation is given as:
y = mx + b
where m is the slope of the line and b is the y-intercept.
- Here, the slope of the line represents the rate per km, which is rupees 5.
- The y-intercept represents the fixed charge for the first kilometer, which is rupees 8.
Hence, the linear equation for the taxi fare can be written as:
y = 5x + 8
**Graph of the Linear Equation**
Now, let's draw the graph of the linear equation y = 5x + 8.
To draw the graph, we need to plot two points on the coordinate plane. We can choose any two values of x and find the corresponding values of y using the linear equation.
Let's choose x = 0 and x = 2.
When x = 0, y = 5(0) + 8 = 8
When x = 2, y = 5(2) + 8 = 18
Hence, the two points are (0, 8) and (2, 18).
We can now plot these two points on the coordinate plane and draw a straight line passing through them.
The graph of the linear equation y = 5x + 8 is given below:
, which represents the fixed charge for the first kilometer, and has a slope of 5, which represents the rate per km beyond the first kilometer. The graph shows that as the distance increases, the fare also increases at a constant rate of rupees 5 per km.
The taxi fare in the city is given as follows:
- For the first kilometer, the fare is rupees 8.
- For the subsequent distance, it is rupees 5 per KM.
Let's take the distance covered as x km and the total fare as rupees y. To find the linear equation for this information, we need to use the concept of slope-intercept form of a linear equation.
The slope-intercept form of a linear equation is given as:
y = mx + b
where m is the slope of the line and b is the y-intercept.
- Here, the slope of the line represents the rate per km, which is rupees 5.
- The y-intercept represents the fixed charge for the first kilometer, which is rupees 8.
Hence, the linear equation for the taxi fare can be written as:
y = 5x + 8
**Graph of the Linear Equation**
Now, let's draw the graph of the linear equation y = 5x + 8.
To draw the graph, we need to plot two points on the coordinate plane. We can choose any two values of x and find the corresponding values of y using the linear equation.
Let's choose x = 0 and x = 2.
When x = 0, y = 5(0) + 8 = 8
When x = 2, y = 5(2) + 8 = 18
Hence, the two points are (0, 8) and (2, 18).
We can now plot these two points on the coordinate plane and draw a straight line passing through them.
The graph of the linear equation y = 5x + 8 is given below:
 https://www.edurev.in/uploads/image/1618923619_linear-graph.png) | ) |
The x-axis represents the distance covered in km and the y-axis represents the fare in rupees. The line passes through the point (0, 8), which represents the fixed charge for the first kilometer, and has a slope of 5, which represents the rate per km beyond the first kilometer. The graph shows that as the distance increases, the fare also increases at a constant rate of rupees 5 per km.
Community Answer
The taxi fare in the city is as follows : for the first kilometer,the ...
The answer will come y = 5x +3
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The taxi fare in the city is as follows : for the first kilometer,the fare is rupees 8 and for the subsequent distance it is rupees 5 per KM . Taking the distance covered as x km and toal fare as rupees y, write a linear equation for this information , and draw its graph.?
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The taxi fare in the city is as follows : for the first kilometer,the fare is rupees 8 and for the subsequent distance it is rupees 5 per KM . Taking the distance covered as x km and toal fare as rupees y, write a linear equation for this information , and draw its graph.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The taxi fare in the city is as follows : for the first kilometer,the fare is rupees 8 and for the subsequent distance it is rupees 5 per KM . Taking the distance covered as x km and toal fare as rupees y, write a linear equation for this information , and draw its graph.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The taxi fare in the city is as follows : for the first kilometer,the fare is rupees 8 and for the subsequent distance it is rupees 5 per KM . Taking the distance covered as x km and toal fare as rupees y, write a linear equation for this information , and draw its graph.?.
The taxi fare in the city is as follows : for the first kilometer,the fare is rupees 8 and for the subsequent distance it is rupees 5 per KM . Taking the distance covered as x km and toal fare as rupees y, write a linear equation for this information , and draw its graph.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about The taxi fare in the city is as follows : for the first kilometer,the fare is rupees 8 and for the subsequent distance it is rupees 5 per KM . Taking the distance covered as x km and toal fare as rupees y, write a linear equation for this information , and draw its graph.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The taxi fare in the city is as follows : for the first kilometer,the fare is rupees 8 and for the subsequent distance it is rupees 5 per KM . Taking the distance covered as x km and toal fare as rupees y, write a linear equation for this information , and draw its graph.?.
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