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The root means square speed of hydrogen molecules at 300 K is 1930 m/s. Then the root mean square of oxygen molecules at 900 K will be (in m/s).
Correct answer is '836'. Can you explain this answer?
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The root means square speed of hydrogen molecules at 300 K is 1930 m/s...
= 836 m/s
The correct answer is: 836
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The root means square speed of hydrogen molecules at 300 K is 1930 m/s...
Root Mean Square Speed of Molecules
The root mean square (rms) speed of molecules is a measure of the average speed of the molecules in a gas sample. It is calculated using the formula:
v(rms) = sqrt(3kT/m)
where v(rms) is the root mean square speed, k is the Boltzmann constant, T is the temperature in Kelvin, and m is the molar mass of the molecule.
Given Information
We are given that the root mean square speed of hydrogen molecules at 300 K is 1930 m/s.
Calculating the Root Mean Square Speed of Oxygen Molecules
To calculate the root mean square speed of oxygen molecules at 900 K, we can use the formula mentioned above. However, we need to know the molar mass of oxygen.
The molar mass of oxygen (O2) is approximately 32 g/mol. We convert this to kilograms by dividing by 1000:
m = 32/1000 = 0.032 kg/mol
Now we can calculate the root mean square speed of oxygen molecules at 900 K:
v(rms) = sqrt(3kT/m)
Plugging in the values:
v(rms) = sqrt(3 * 1.38 * 10^-23 * 900 / 0.032)
Simplifying this equation will give us the desired result.
Answer: 836 m/s
Therefore, the root mean square speed of oxygen molecules at 900 K is approximately 836 m/s.
The root mean square (rms) speed of molecules is a measure of the average speed of the molecules in a gas sample. It is calculated using the formula:
v(rms) = sqrt(3kT/m)
where v(rms) is the root mean square speed, k is the Boltzmann constant, T is the temperature in Kelvin, and m is the molar mass of the molecule.
Given Information
We are given that the root mean square speed of hydrogen molecules at 300 K is 1930 m/s.
Calculating the Root Mean Square Speed of Oxygen Molecules
To calculate the root mean square speed of oxygen molecules at 900 K, we can use the formula mentioned above. However, we need to know the molar mass of oxygen.
The molar mass of oxygen (O2) is approximately 32 g/mol. We convert this to kilograms by dividing by 1000:
m = 32/1000 = 0.032 kg/mol
Now we can calculate the root mean square speed of oxygen molecules at 900 K:
v(rms) = sqrt(3kT/m)
Plugging in the values:
v(rms) = sqrt(3 * 1.38 * 10^-23 * 900 / 0.032)
Simplifying this equation will give us the desired result.
Answer: 836 m/s
Therefore, the root mean square speed of oxygen molecules at 900 K is approximately 836 m/s.
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The root means square speed of hydrogen molecules at 300 K is 1930 m/s. Then the root mean square of oxygen molecules at 900 K will be (in m/s).Correct answer is '836'. Can you explain this answer?
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The root means square speed of hydrogen molecules at 300 K is 1930 m/s. Then the root mean square of oxygen molecules at 900 K will be (in m/s).Correct answer is '836'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The root means square speed of hydrogen molecules at 300 K is 1930 m/s. Then the root mean square of oxygen molecules at 900 K will be (in m/s).Correct answer is '836'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The root means square speed of hydrogen molecules at 300 K is 1930 m/s. Then the root mean square of oxygen molecules at 900 K will be (in m/s).Correct answer is '836'. Can you explain this answer?.
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