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Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. Given μO = 1.658, μe = 1.486 and c = 3 x 1010 cm/s.
- a)3.05 x 108 m/s
- b)2.02 x 108 m/s
- c)1.01 x 108m/s
- d)4.11 x 108 m/s
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Calculate the velocities of extraordinary rays in calcite crystal in a...
The velocity of the O-wave in the crystal is
= 1.81 x 108 m/s
The velocity of the E-wave in the crystal normal to be optic axis is
= 2.02 x 108 m/s
The correct answer is: = 2.02 x 108 m/s
= 1.81 x 108 m/s
The velocity of the E-wave in the crystal normal to be optic axis is
= 2.02 x 108 m/s
The correct answer is: = 2.02 x 108 m/s
Most Upvoted Answer
Calculate the velocities of extraordinary rays in calcite crystal in a...
To calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis, we need to use the equation for the index of refraction for extraordinary rays in calcite crystal.
The equation for the index of refraction for extraordinary rays in calcite crystal is:
n = √(ε * μ)
Where:
n is the index of refraction,
ε is the dielectric constant, and
μ is the permeability.
Given that the dielectric constant (ε) and permeability (μ) for calcite crystal are not provided, it is difficult to give a specific value for the velocities of extraordinary rays in a plane perpendicular to the optic axis.
However, it is known that the index of refraction for extraordinary rays in calcite crystal is usually around 1.658. The velocity of light in a medium can be calculated using the formula:
v = c / n
Where:
v is the velocity of light in the medium, and
c is the speed of light in a vacuum (approximately 3 x 10^8 m/s).
Using the index of refraction for extraordinary rays in calcite crystal (n = 1.658) and the speed of light in a vacuum (c = 3 x 10^8 m/s), we can calculate the velocity of extraordinary rays in a plane perpendicular to the optic axis.
v = (3 x 10^8 m/s) / 1.658 ≈ 1.81 x 10^8 m/s
Therefore, the velocity of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis is approximately 1.81 x 10^8 m/s.
The equation for the index of refraction for extraordinary rays in calcite crystal is:
n = √(ε * μ)
Where:
n is the index of refraction,
ε is the dielectric constant, and
μ is the permeability.
Given that the dielectric constant (ε) and permeability (μ) for calcite crystal are not provided, it is difficult to give a specific value for the velocities of extraordinary rays in a plane perpendicular to the optic axis.
However, it is known that the index of refraction for extraordinary rays in calcite crystal is usually around 1.658. The velocity of light in a medium can be calculated using the formula:
v = c / n
Where:
v is the velocity of light in the medium, and
c is the speed of light in a vacuum (approximately 3 x 10^8 m/s).
Using the index of refraction for extraordinary rays in calcite crystal (n = 1.658) and the speed of light in a vacuum (c = 3 x 10^8 m/s), we can calculate the velocity of extraordinary rays in a plane perpendicular to the optic axis.
v = (3 x 10^8 m/s) / 1.658 ≈ 1.81 x 10^8 m/s
Therefore, the velocity of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis is approximately 1.81 x 10^8 m/s.
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Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. GivenμO =1.658,μe=1.486 and c = 3 x 1010cm/s.a)3.05 x 108m/sb)2.02 x 108m/sc)1.01 x 108m/sd)4.11 x 108m/sCorrect answer is option 'B'. Can you explain this answer?
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Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. GivenμO =1.658,μe=1.486 and c = 3 x 1010cm/s.a)3.05 x 108m/sb)2.02 x 108m/sc)1.01 x 108m/sd)4.11 x 108m/sCorrect answer is option 'B'. Can you explain this answer? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. GivenμO =1.658,μe=1.486 and c = 3 x 1010cm/s.a)3.05 x 108m/sb)2.02 x 108m/sc)1.01 x 108m/sd)4.11 x 108m/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. GivenμO =1.658,μe=1.486 and c = 3 x 1010cm/s.a)3.05 x 108m/sb)2.02 x 108m/sc)1.01 x 108m/sd)4.11 x 108m/sCorrect answer is option 'B'. Can you explain this answer?.
Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. GivenμO =1.658,μe=1.486 and c = 3 x 1010cm/s.a)3.05 x 108m/sb)2.02 x 108m/sc)1.01 x 108m/sd)4.11 x 108m/sCorrect answer is option 'B'. Can you explain this answer? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. GivenμO =1.658,μe=1.486 and c = 3 x 1010cm/s.a)3.05 x 108m/sb)2.02 x 108m/sc)1.01 x 108m/sd)4.11 x 108m/sCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the velocities of extraordinary rays in calcite crystal in a plane perpendicular to the optic axis. GivenμO =1.658,μe=1.486 and c = 3 x 1010cm/s.a)3.05 x 108m/sb)2.02 x 108m/sc)1.01 x 108m/sd)4.11 x 108m/sCorrect answer is option 'B'. Can you explain this answer?.
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