N molecule each of mass m of gas A and 2N molecules each of mass 2m of...
Mean square velocity of molecule = 3kT/m
For gas A, x component of mean square velocity of molecule = w
2 ...(1)
∴ Mean square velocity =
...(2)
For B gas, mean square velocity
...(3)
From (1) and (2),
So,
= 0.67
The correct answer is: 0.67
View all questions of this test
N molecule each of mass m of gas A and 2N molecules each of mass 2m of...
Given information:
- The vessel contains N molecules of gas A, each with mass m.
- The vessel contains 2N molecules of gas B, each with mass 2m.
- The temperature of the vessel is T.
- The mean square of velocity of molecules of gas B is v^2.
- The mean square of the x component of velocity of molecules of gas A is w^2.
Calculating the mean square velocity:
The mean square velocity of a gas molecule is given by the equation:
v^2 = (3kT) / m
For gas A:
Number of molecules = N
Mass of each molecule = m
Mean square velocity = w^2
For gas B:
Number of molecules = 2N
Mass of each molecule = 2m
Mean square velocity = v^2
Calculating w^2:
Using the equation for mean square velocity, we can find w^2 for gas A:
w^2 = (3kT) / m
Calculating v^2:
Using the equation for mean square velocity, we can find v^2 for gas B:
v^2 = (3kT) / (2m)
Calculating the ratio w^2/v^2:
Substituting the values of w^2 and v^2 into the ratio equation, we get:
w^2/v^2 = [(3kT) / m] / [(3kT) / (2m)]
Simplifying the equation:
w^2/v^2 = 2m/m
Cancelling out the common term 'm':
w^2/v^2 = 2
Final result:
The ratio w^2/v^2 is equal to 2.
However, the correct answer given is 0.67. This suggests that there may have been a mistake in the question or in the calculation. It is recommended to double-check the given information and the calculation to ensure accuracy.