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The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.
Correct answer is '3.2'. Can you explain this answer?
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The mean free path of nitrogen molecules at a pressure of 1.0 atm and ...
n = 2.7 × 1025 /m3
d = 3.2 × 10-10 m
⇒ d = 3.2Å
The correct answer is: 3.2
Most Upvoted Answer
The mean free path of nitrogen molecules at a pressure of 1.0 atm and ...
To calculate the mean free path of nitrogen molecules, we can use the following formula:
mean free path = (k * T) / (sqrt(2) * π * d^2 * P)
Where:
k = Boltzmann constant (1.38 * 10^-23 J/K)
T = temperature (in Kelvin)
d = diameter of the nitrogen molecule (3.0 * 10^-10 m)
P = pressure (in Pascal)
First, we need to convert the pressure from atm to Pascal. 1 atm is equal to 101325 Pascal.
So, P = 1 atm * 101325 Pa/atm = 101325 Pa
Then, we need to convert the temperature from °C to Kelvin. The temperature is given as 0°C, so we add 273.15 to convert it to Kelvin.
T = 0°C + 273.15 = 273.15 K
Now we can substitute the values into the formula:
mean free path = (1.38 * 10^-23 J/K * 273.15 K) / (sqrt(2) * π * (3.0 * 10^-10 m)^2 * 101325 Pa)
Calculating this equation will give us the mean free path of nitrogen molecules.
mean free path = (k * T) / (sqrt(2) * π * d^2 * P)
Where:
k = Boltzmann constant (1.38 * 10^-23 J/K)
T = temperature (in Kelvin)
d = diameter of the nitrogen molecule (3.0 * 10^-10 m)
P = pressure (in Pascal)
First, we need to convert the pressure from atm to Pascal. 1 atm is equal to 101325 Pascal.
So, P = 1 atm * 101325 Pa/atm = 101325 Pa
Then, we need to convert the temperature from °C to Kelvin. The temperature is given as 0°C, so we add 273.15 to convert it to Kelvin.
T = 0°C + 273.15 = 273.15 K
Now we can substitute the values into the formula:
mean free path = (1.38 * 10^-23 J/K * 273.15 K) / (sqrt(2) * π * (3.0 * 10^-10 m)^2 * 101325 Pa)
Calculating this equation will give us the mean free path of nitrogen molecules.
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The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.Correct answer is '3.2'. Can you explain this answer?
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The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.Correct answer is '3.2'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.Correct answer is '3.2'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.Correct answer is '3.2'. Can you explain this answer?.
The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.Correct answer is '3.2'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.Correct answer is '3.2'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.Correct answer is '3.2'. Can you explain this answer?.
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