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22gm of CO2 at 27°C is mixed with 16 gm of O2 at 37°C. The temperature of the mixture (in °C) is?
    Correct answer is '32'. Can you explain this answer?
    Verified Answer
    22gm of CO2 at 27°C is mixed with 16 gm of O2 at 37°C. The tem...
    Let t be the temperature of mixture
    Heat gained by CO2 = Heat lost by O2

    ⇒ t = 32°C
    The correct answer is: 32
    View all questions of this test
    Most Upvoted Answer
    22gm of CO2 at 27°C is mixed with 16 gm of O2 at 37°C. The tem...
    To calculate the volume of CO2 at 27°C, we need to use the ideal gas law equation:

    PV = nRT

    Where:
    P = pressure (unknown)
    V = volume of CO2 (unknown)
    n = number of moles of CO2 (given as 22g)
    R = ideal gas constant (0.0821 L·atm/(mol·K))
    T = temperature in Kelvin (27°C + 273.15 = 300.15K)

    Rearranging the equation, we have:

    V = (nRT) / P

    Substituting the given values:

    V = (22g * 0.0821 L·atm/(mol·K) * 300.15K) / P

    Now, we need to determine the pressure (P) in order to calculate the volume of CO2.
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    22gm of CO2 at 27°C is mixed with 16 gm of O2 at 37°C. The temperature of the mixture (in °C) is?Correct answer is '32'. Can you explain this answer?
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    22gm of CO2 at 27°C is mixed with 16 gm of O2 at 37°C. The temperature of the mixture (in °C) is?Correct answer is '32'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about 22gm of CO2 at 27°C is mixed with 16 gm of O2 at 37°C. The temperature of the mixture (in °C) is?Correct answer is '32'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 22gm of CO2 at 27°C is mixed with 16 gm of O2 at 37°C. The temperature of the mixture (in °C) is?Correct answer is '32'. Can you explain this answer?.
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