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An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2 gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X is
- a)1-butanol
- b)2-methyl-1-pentanol
- c)2-butanol
- d)Either (a) or (b)
Correct answer is option 'D'. Can you explain this answer?
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An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I ...
X must be a primary alcohol as indicated by Victor Meyer's test. Both (a) and (b) are primary satisfy the condition.
Most Upvoted Answer
An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I ...
Identification of compound X
To identify compound X, we need to analyze the given reactions and the properties of X.
Reaction 1: X + I2/red-P -> C4H9I
In this reaction, compound X reacts with iodine in the presence of a reducing agent (red-P) to form compound C4H9I. This reaction is known as the iodination of alcohols.
Reaction 2: C4H9I + AgNO2 -> C4H9NO2 (Y)
In this reaction, compound C4H9I reacts with silver nitrite (AgNO2) to form compound C4H9NO2, which is denoted as Y. This reaction is known as the Sandmeyer reaction.
Reaction 3: Y + HNO2 -> Blue solution (which turns red on making solution slightly alkaline)
In this reaction, compound Y reacts with nitrous acid (HNO2) to form a blue solution. When the solution is made slightly alkaline, the blue solution turns red.
Analysis and reasoning:
- From Reaction 1, we can conclude that compound X is an alcohol because alcohols react with iodine in the presence of a reducing agent to form alkyl iodides.
- The molecular formula of X is C4H10O, which indicates that it is a pentanol. The possible pentanol is 1-pentanol (C5H12O) or 2-methyl-1-pentanol (C6H14O).
- However, in Reaction 2, compound C4H9I is formed, which indicates that X is a butanol (C4H9OH) and not a pentanol. This rules out the possibility of X being 2-methyl-1-pentanol.
- Therefore, the only possible identity of X is 1-butanol (C4H9OH).
- Since 1-butanol fits the given molecular formula, reactions, and properties, the correct answer is option D, which states that X can be either 1-butanol or 2-methyl-1-pentanol.
Conclusion:
Based on the given reactions and properties, the compound X is most likely 1-butanol (C4H9OH).
To identify compound X, we need to analyze the given reactions and the properties of X.
Reaction 1: X + I2/red-P -> C4H9I
In this reaction, compound X reacts with iodine in the presence of a reducing agent (red-P) to form compound C4H9I. This reaction is known as the iodination of alcohols.
Reaction 2: C4H9I + AgNO2 -> C4H9NO2 (Y)
In this reaction, compound C4H9I reacts with silver nitrite (AgNO2) to form compound C4H9NO2, which is denoted as Y. This reaction is known as the Sandmeyer reaction.
Reaction 3: Y + HNO2 -> Blue solution (which turns red on making solution slightly alkaline)
In this reaction, compound Y reacts with nitrous acid (HNO2) to form a blue solution. When the solution is made slightly alkaline, the blue solution turns red.
Analysis and reasoning:
- From Reaction 1, we can conclude that compound X is an alcohol because alcohols react with iodine in the presence of a reducing agent to form alkyl iodides.
- The molecular formula of X is C4H10O, which indicates that it is a pentanol. The possible pentanol is 1-pentanol (C5H12O) or 2-methyl-1-pentanol (C6H14O).
- However, in Reaction 2, compound C4H9I is formed, which indicates that X is a butanol (C4H9OH) and not a pentanol. This rules out the possibility of X being 2-methyl-1-pentanol.
- Therefore, the only possible identity of X is 1-butanol (C4H9OH).
- Since 1-butanol fits the given molecular formula, reactions, and properties, the correct answer is option D, which states that X can be either 1-butanol or 2-methyl-1-pentanol.
Conclusion:
Based on the given reactions and properties, the compound X is most likely 1-butanol (C4H9OH).
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An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer?
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An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer?.
An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer?.
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