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An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2 gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X is
  • a)
    1-butanol
  • b)
    2-methyl-1-pentanol
  • c)
    2-butanol
  • d)
    Either (a) or (b)
Correct answer is option 'D'. Can you explain this answer?
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An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I ...
X must be a primary alcohol as indicated by Victor Meyer's test. Both (a) and (b) are primary satisfy the condition.
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An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I ...
Identification of compound X

To identify compound X, we need to analyze the given reactions and the properties of X.

Reaction 1: X + I2/red-P -> C4H9I

In this reaction, compound X reacts with iodine in the presence of a reducing agent (red-P) to form compound C4H9I. This reaction is known as the iodination of alcohols.

Reaction 2: C4H9I + AgNO2 -> C4H9NO2 (Y)

In this reaction, compound C4H9I reacts with silver nitrite (AgNO2) to form compound C4H9NO2, which is denoted as Y. This reaction is known as the Sandmeyer reaction.

Reaction 3: Y + HNO2 -> Blue solution (which turns red on making solution slightly alkaline)

In this reaction, compound Y reacts with nitrous acid (HNO2) to form a blue solution. When the solution is made slightly alkaline, the blue solution turns red.

Analysis and reasoning:
- From Reaction 1, we can conclude that compound X is an alcohol because alcohols react with iodine in the presence of a reducing agent to form alkyl iodides.
- The molecular formula of X is C4H10O, which indicates that it is a pentanol. The possible pentanol is 1-pentanol (C5H12O) or 2-methyl-1-pentanol (C6H14O).
- However, in Reaction 2, compound C4H9I is formed, which indicates that X is a butanol (C4H9OH) and not a pentanol. This rules out the possibility of X being 2-methyl-1-pentanol.
- Therefore, the only possible identity of X is 1-butanol (C4H9OH).
- Since 1-butanol fits the given molecular formula, reactions, and properties, the correct answer is option D, which states that X can be either 1-butanol or 2-methyl-1-pentanol.

Conclusion:
Based on the given reactions and properties, the compound X is most likely 1-butanol (C4H9OH).
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Read the passage given below and answer the following questions:Reductive alkylation is the term applied to the process of introducing alkyl groups into ammonia or a primary or secondary amine by means of an aldehyde or ketone in the presence of a reducing agent. The present discussion is limited to those reductive alkylations in which the reducing agent is hydrogen and a catalyst or "nascent" hydrogen, usually from a metalacid combination; most of these reductive alkylations have been carried out with hydrogen and a catalyst. The principal variation excluded is that in which the reducing agent is formic acid or one of its derivatives; this modification is known as the Leuckart reaction. The process of reductive alkylation of ammonia consists in the addition of ammonia to a carbonyl compound and reduction of the addition compound or its dehydration product. The reaction usually is carried out in ethanol solution when the reduction is to be effected catalytically:Since the primary amine is formed in the presence of the aldehyde it may react in the same way as ammonia, yielding an additional compound, a Schiff's base (RCH= NCH2R) and finally, a secondary amine. Similarly, the primary amine may react with the imine, forming an addition product which also is reduced to a secondary amine Finally, the secondary amine may react with either the aldehyde or the imine to give products which are reduced to tertiary amines.Similar reactions may occur when the carbonyl compound employed is a ketone.Q. The reaction of ammonia and its derivatives with aldehydes is called

An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer?
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An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound C4H10O (X) on reaction with I2/red-P give s C4H9I which on further reaction with AgNO2gives C4H9NO2 (Y). Y on treatment with HNO2 forms a blue solution which turns to red on making solution slightly alkaline. The possible identity of X isa)1-butanolb)2-methyl-1-pentanolc)2-butanold)Either (a) or (b)Correct answer is option 'D'. Can you explain this answer?.
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