The sum of natural numbers upto 200 excluding those divisible by 5 is ...
**The Sum of Natural Numbers up to 200 Excluding Those Divisible by 5**
To find the sum of natural numbers up to 200 excluding those divisible by 5, we need to follow a few steps. Let's break down the process into smaller sections:
**1. Identify the Natural Numbers up to 200**
First, we need to identify all the natural numbers up to 200. Natural numbers are positive integers starting from 1, so we need to list all the numbers from 1 to 200.
**2. Exclude Numbers Divisible by 5**
Next, we need to exclude numbers that are divisible by 5. By dividing each number from 1 to 200 by 5, we can identify the numbers that are divisible by 5. These numbers will not be included in the sum.
**3. Calculate the Sum**
Finally, we can calculate the sum of the remaining numbers.
Let's go through these steps in detail:
**1. Identify the Natural Numbers up to 200**
Natural numbers are positive integers starting from 1. So, we need to list all the numbers from 1 to 200.
Natural numbers up to 200: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ..., 199, 200
**2. Exclude Numbers Divisible by 5**
To exclude numbers divisible by 5, we need to divide each number from 1 to 200 by 5 and check if the remainder is zero. If the remainder is zero, it means the number is divisible by 5 and should be excluded.
Numbers divisible by 5: 5, 10, 15, 20, ..., 195, 200
**3. Calculate the Sum**
Now that we have identified the natural numbers and excluded the numbers divisible by 5, we can calculate the sum of the remaining numbers.
To find the sum of these numbers, we can use the formula for the sum of an arithmetic series, which is given by:
Sum = (n/2)(first term + last term)
In this case, the first term is 1, the last term is 200, and n is the number of terms.
To find the number of terms, we can subtract the number of excluded terms (divisible by 5) from the total number of terms (200).
Number of terms = Total number of terms - Number of excluded terms
Number of terms = 200 - (200/5)
Number of terms = 200 - 40
Number of terms = 160
Now, we can substitute the values into the formula:
Sum = (160/2)(1 + 200)
Sum = 80(201)
Sum = 16,080
Therefore, the sum of natural numbers up to 200 excluding those divisible by 5 is 16,080.