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The sum of natural numbers between 200 and 400,which are divisible by 7,is?
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The sum of natural numbers between 200 and 400,which are divisible by...
AP= 203, 210, 317-----399
a=203
d=7
tn=399
tn =a+(n-1)d
399=203 + (n-1)7
196/7 =n-1
28+1=n
therefore n=29
sum= 29/2 (203+399)
=14.5× 602
=8729
a=203
d=7
tn=399
tn =a+(n-1)d
399=203 + (n-1)7
196/7 =n-1
28+1=n
therefore n=29
sum= 29/2 (203+399)
=14.5× 602
=8729
Community Answer
The sum of natural numbers between 200 and 400,which are divisible by...
Sum of Natural Numbers Divisible by 7 between 200 and 400
To find the sum of natural numbers between 200 and 400 that are divisible by 7, we need to identify the numbers first.
Finding the Numbers Divisible by 7
- We need to find the first and last numbers that are divisible by 7 in the given range.
- The first number divisible by 7 in the range is 203 (7 x 29).
- The last number divisible by 7 in the range is 392 (7 x 56).
Calculating the Number of Terms
- To find the total number of terms, we can use the formula:
Number of terms = ((Last term - First term) / Common difference) + 1
- In this case, the common difference is 7.
- So, the number of terms = ((392 - 203) / 7) + 1 = 20.
Calculating the Sum
- The sum of an arithmetic series is given by the formula:
Sum = (n/2) x (first term + last term)
- Substituting the values, we get:
Sum = (20/2) x (203 + 392) = 10 x 595 = 5950.
Therefore, the sum of natural numbers between 200 and 400 that are divisible by 7 is 5950.
To find the sum of natural numbers between 200 and 400 that are divisible by 7, we need to identify the numbers first.
Finding the Numbers Divisible by 7
- We need to find the first and last numbers that are divisible by 7 in the given range.
- The first number divisible by 7 in the range is 203 (7 x 29).
- The last number divisible by 7 in the range is 392 (7 x 56).
Calculating the Number of Terms
- To find the total number of terms, we can use the formula:
Number of terms = ((Last term - First term) / Common difference) + 1
- In this case, the common difference is 7.
- So, the number of terms = ((392 - 203) / 7) + 1 = 20.
Calculating the Sum
- The sum of an arithmetic series is given by the formula:
Sum = (n/2) x (first term + last term)
- Substituting the values, we get:
Sum = (20/2) x (203 + 392) = 10 x 595 = 5950.
Therefore, the sum of natural numbers between 200 and 400 that are divisible by 7 is 5950.
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The sum of natural numbers between 200 and 400,which are divisible by 7,is?
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The sum of natural numbers between 200 and 400,which are divisible by 7,is? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The sum of natural numbers between 200 and 400,which are divisible by 7,is? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of natural numbers between 200 and 400,which are divisible by 7,is?.
The sum of natural numbers between 200 and 400,which are divisible by 7,is? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The sum of natural numbers between 200 and 400,which are divisible by 7,is? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of natural numbers between 200 and 400,which are divisible by 7,is?.
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