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Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter is
- a)0, 1, 3, 7, 15, 14, 12, 8, 0
- b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0
- c)0, 2, 4, 6, 8, 10, 12, 14, 0
- d)0, 8, 12, 14, 15, 7, 3, 1, 0
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Consider a 4-bit Johnson counter with an initial value of 0000. The co...
0000 - 0
1000 - 8
1100 - 12
and so on.
1000 - 8
1100 - 12
and so on.
Most Upvoted Answer
Consider a 4-bit Johnson counter with an initial value of 0000. The co...
Introduction to Johnson Counter
A Johnson counter, also known as a twisted ring counter, is a type of shift register that provides a specific sequence of binary values. In a 4-bit Johnson counter, the counting mechanism involves feedback from the last flip-flop back into the first, effectively doubling the counting sequence of a standard ring counter.
Counting Sequence Explanation
Starting from an initial value of 0000, the Johnson counter generates the following values:
- State 1: 0000 (initial state)
- State 2: 0001 (1 is added, output of the first flip-flop)
- State 3: 0011 (the output of the first two flip-flops)
- State 4: 0111 (the last flip-flop flips to 1)
- State 5: 1111 (all flip-flops are set)
- State 6: 1110 (the first flip-flop resets)
- State 7: 1100 (the second flip-flop resets)
- State 8: 1000 (the third flip-flop resets)
- State 9: 0000 (returns to the initial state)
Final Sequence Representation
The unique sequence generated by the 4-bit Johnson counter is as follows:
- 0000 (0 in decimal)
- 1000 (8 in decimal)
- 1100 (12 in decimal)
- 1110 (14 in decimal)
- 1111 (15 in decimal)
- 0111 (7 in decimal)
- 0011 (3 in decimal)
- 0001 (1 in decimal)
- 0000 (returns to 0 in decimal)
This forms the complete sequence: 0, 8, 12, 14, 15, 7, 3, 1, 0.
Conclusion
Thus, the correct answer for the counting sequence of a 4-bit Johnson counter starting from 0000 is option D.
A Johnson counter, also known as a twisted ring counter, is a type of shift register that provides a specific sequence of binary values. In a 4-bit Johnson counter, the counting mechanism involves feedback from the last flip-flop back into the first, effectively doubling the counting sequence of a standard ring counter.
Counting Sequence Explanation
Starting from an initial value of 0000, the Johnson counter generates the following values:
- State 1: 0000 (initial state)
- State 2: 0001 (1 is added, output of the first flip-flop)
- State 3: 0011 (the output of the first two flip-flops)
- State 4: 0111 (the last flip-flop flips to 1)
- State 5: 1111 (all flip-flops are set)
- State 6: 1110 (the first flip-flop resets)
- State 7: 1100 (the second flip-flop resets)
- State 8: 1000 (the third flip-flop resets)
- State 9: 0000 (returns to the initial state)
Final Sequence Representation
The unique sequence generated by the 4-bit Johnson counter is as follows:
- 0000 (0 in decimal)
- 1000 (8 in decimal)
- 1100 (12 in decimal)
- 1110 (14 in decimal)
- 1111 (15 in decimal)
- 0111 (7 in decimal)
- 0011 (3 in decimal)
- 0001 (1 in decimal)
- 0000 (returns to 0 in decimal)
This forms the complete sequence: 0, 8, 12, 14, 15, 7, 3, 1, 0.
Conclusion
Thus, the correct answer for the counting sequence of a 4-bit Johnson counter starting from 0000 is option D.
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Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer?
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Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer?.
Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer?.
Solutions for Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a 4-bit Johnson counter with an initial value of 0000. The counting sequence of this counter isa)0, 1, 3, 7, 15, 14, 12, 8, 0b)0, 1, 3, 5, 7, 9, 11, 13, 15, 0c)0, 2, 4, 6, 8, 10, 12, 14, 0d)0, 8, 12, 14, 15, 7, 3, 1, 0Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
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