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Breadth First Search (BFS) is started on a binary tree beginning from the root vertex. There is a vertex t  at a distance four from the root. If t is the  n-th vertex in this BFS traversal, then the maximum possible value of n is _________.
    Correct answer is '31'. Can you explain this answer?
    Verified Answer
    Breadth First Search (BFS) is started on a binary tree beginning from ...
    No of nodes at level 0(root) of tree =>1
    No of nodes at level 1 of tree =>2
    No of nodes at level 2 of tree =>4
    No of nodes at level 3 of tree =>8
    No of nodes at level 4 of tree =>16
    Last node in level 4th is the node we are looking for => 1+2+4+8+16 => 31
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    Breadth First Search (BFS) is started on a binary tree beginning from ...
    Understanding BFS in a Binary Tree
    Breadth First Search (BFS) explores nodes level by level, starting from the root. In a binary tree, each node can have up to two children, which leads to an exponential growth in the number of nodes at each level.
    Tree Structure
    - Level 0 (Root): 1 node
    - Level 1: 2 nodes
    - Level 2: 4 nodes
    - Level 3: 8 nodes
    - Level 4: 16 nodes
    By the fourth level, the total number of nodes is the sum of all nodes up to that level.
    Calculating Total Nodes
    - Total nodes from Level 0 to Level 4:
    - Level 0: 1
    - Level 1: 2
    - Level 2: 4
    - Level 3: 8
    - Level 4: 16
    This totals to: 1 + 2 + 4 + 8 + 16 = 31
    Position of Vertex t
    - Since vertex t is at distance four from the root, it resides on Level 4.
    - In BFS, all nodes at Level 4 will be explored after all nodes at Levels 0, 1, 2, and 3.
    - The maximum number of nodes explored before reaching Level 4 is 15 (from Levels 0 to 3).
    Maximum Possible Value of n
    - Adding the nodes from Level 4 (16 nodes) to the previous total (15 nodes):
    - 15 (from Levels 0-3) + 16 (from Level 4) = 31
    Thus, the maximum possible value of n, where t is the n-th vertex in the BFS traversal, is 31.
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