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In the figure given above, the diagonal AC and side DC of square ABCD are extended to form sides of the isosceles triangle CEF where CE = EF. If the length of side CF is 2√2 and the ratio of areas of the triangle CEF to the square ABCD is 1:8, what is the length of the side of square ABCD?
  • a)
    2√2
  • b)
    4
  • c)
    4√2
  • d)
    8
  • e)
    16
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In the figure given above, the diagonal AC and side DC of square ABCD ...
Given
 
Approach
  1. We know that area of square ABCD = side . So, if we can find the area of triangle CEF, we can find the area of square ABCD, which will give us the side length of square ABCD.
  2. In triangle CEF, we only know the side length CF. So, we need to find the lengths of other sides and the angles of the triangle.
  3. Now, we know that diagonals of a square bisects its angles. Also, since AE and DF are straight intersecting lines, ∠ECF = ∠DCA (vertically opposite angles)
    1. Since we now know ∠ECF, we can calculate the other angles of the
      triangle CEF.
Working out
  1. As the diagonals of the square bisect the vertex angles, ∠DCA = 450
    1. Since ∠ECF and ∠DCA are vertically opposite angles, ∠ECF = ∠DCA = 450
3. So, triangle CEF is an isosceles right angled triangle with its hypotenuse equal to 2√2
Using the 45o - 45o  - 90triangle property, we have CE= EF = 2
4. Hence, area of triangle CEF = ½ * CE * EF = ½ * 2* 2 = 2 square centimeters
5. Using the relation  we have Ar(ABCD) = 16
6. Thus, side of square ABCD = √16 = 4 centimeters
Answer : B
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In the figure given above, the diagonal AC and side DC of square ABCD are extended to form sides of the isosceles triangle CEF where CE = EF. If the length of side CF is 2√2 and the ratio of areas of the triangle CEF to the square ABCD is 1:8, what is the length of the side of square ABCD?a)2√2b)4c)4√2d)8e)16Correct answer is option 'B'. Can you explain this answer?
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