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A source is emitting sound with frequency 4371 Hz. Find the magnitude of difference of the two velocities with which the observer must move to observe a frequency that is 20% higher and 20% lower than the actual frequency (in m/s).
    Correct answer is '136'. Can you explain this answer?
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    A source is emitting sound with frequency 4371 Hz. Find the magnitude ...
    fs = frequency of source = 4371 Hz

    When ovserved frequency is 20% higher

    = 68 m/s
    When the observed frequency is 20% lower

    (-) sign indicates that the observer is moving away from the source?
    ∴ Difference of velocities = 68 - (-68)
    = 136 m/s
    The correct answer is: 136
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    A source is emitting sound with frequency 4371 Hz. Find the magnitude of difference of the two velocities with which the observer must move to observe a frequency that is 20% higher and 20% lower than the actual frequency (in m/s).Correct answer is '136'. Can you explain this answer?
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