Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A synchronous motor operating at rated voltag...
Start Learning for Free
A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by?
Most Upvoted Answer
A synchronous motor operating at rated voltage draws 1.0 pu current at...
Question: What is the increase in field current required for a synchronous motor operating at rated voltage to supply an additional reactive power of 0.8 pu?
Solution:
Given:
Steps to Find the Increase in Field Current:
Answer: The increase in field current required for the synchronous motor to supply an additional reactive power of 0.8 pu is -V^2 + 0.0265.
Solution:
Given:
- Synchronous reactance = 1.0 pu
- Armature resistance = negligible
- Rated voltage = V
- Rated current = I = 1.0 pu
- Power factor = 1.0
- Additional reactive power = 0.8 pu
Steps to Find the Increase in Field Current:
- Calculate the rated apparent power of the motor.
S = V*I = V*1.0 = V pu - Calculate the rated active power of the motor.
P = S*power factor = V*1.0 = V pu - Calculate the rated reactive power of the motor.
Q = sqrt(S^2 - P^2) = sqrt(V^2 - V^2) = sqrt(0) = 0 pu - Calculate the total reactive power that the motor has to supply.
Q_total = Q + additional reactive power = 0 + 0.8 = 0.8 pu - Calculate the field current required to supply the additional reactive power using the formula:
Q_total = (3*V^2*E_f)/(2*pi*f*X_s)
Where E_f is the field voltage, f is the frequency, and X_s is the synchronous reactance.
E_f = (2*pi*f*X_s*Q_total)/(3*V^2) = (2*pi*50*1.0*0.8)/(3*V^2) = 0.0265/V - Calculate the increase in field current required using the formula:
delta(I_f) = (E_f - E_rated)/X_s
Where E_rated is the rated field voltage.
E_rated = V/X_s = V/1.0 = V
delta(I_f) = (0.0265/V - V)/1.0 = -V^2 + 0.0265
Answer: The increase in field current required for the synchronous motor to supply an additional reactive power of 0.8 pu is -V^2 + 0.0265.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by?
Question Description
A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by?.
A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by?.
Solutions for A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? defined & explained in the simplest way possible. Besides giving the explanation of
A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by?, a detailed solution for A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? has been provided alongside types of A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? theory, EduRev gives you an
ample number of questions to practice A synchronous motor operating at rated voltage draws 1.0 pu current at 1.0 power factor . the machine parameters are synchronous reactance 1.0 pu armature resistance negligible . Apart from supplying this rated power if the motor has to supply an additional reactive power of o.8 pu then the field current has to be increased by? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup