In triangle PQR length of the side QR is less than twice the length of...
In Δ PQR,
QR +2 = 2PQ
QR = 2PQ - 2 ------- (2)
PR = PQ + 10 ----- (2)
Perimeter = 40 m
PQ + QR + Rp = 40
Putting the value of PQ and QR from equation (1) and (2),
Pq + 2PQ - 2 + PQ +10 = 40
4PQ = 32
PQ = 8 cm which is the smallest side of the triangle.
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In triangle PQR length of the side QR is less than twice the length of...
Given:
- Length of QR < 2(pq)="" -="" />
- Length of PR = PQ + 10
- Perimeter of PQR = 40
To find:
- Length of smallest side of PQR
Solution:
Let's assume the length of PQ to be x.
From the given information, we can create two equations:
- QR < 2x="" -="" 2="" />
- PR = x + 10
We know that the perimeter of a triangle is the sum of all its sides.
So,
PQ + QR + PR = 40
Substituting the values of QR and PR from the above equations, we get:
x + (2x - 2) + (x + 10) = 40
Simplifying the above equation, we get:
4x + 8 = 40
4x = 32
x = 8
Therefore, the length of PQ is 8 cm.
To find the smallest side of the triangle, we need to compare PQ, QR, and PR.
- PQ = 8 cm
- QR < 2(8)="" -="" 2="14" cm="" />
- PR = 8 + 10 = 18 cm
Therefore, the smallest side of the triangle is PQ with a length of 8 cm.
Hence, the correct option is (B) 8 cm.
In triangle PQR length of the side QR is less than twice the length of...
Let Length of PQ be X.. length of PR = X + 10 , length of QR = 2X - 2...
X + X+10+2X-2 = 40
4X = 32
X = 8 , the other two sides Will be 18, 14.
8 is the smallest side, hence the correct answer..