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The Particular Integral (PI) of the differential equation (D2 – 5D + 6)y = x is given as y = mx + c. Find the value of c.
    Correct answer is '0.138'. Can you explain this answer?
    Verified Answer
    The Particular Integral (PI) of the differential equation(D2– 5D...

    y = mx + c
    ⇒ c = 5/36 = 0.138
    The correct answer is: 0.138
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    Most Upvoted Answer
    The Particular Integral (PI) of the differential equation(D2– 5D...
    Explanation:

    Finding the Particular Integral (PI)
    The differential equation given is (D^2 - 5D + 6)y = x. To find the particular integral (PI), assume y = mx + c, where m and c are constants to be determined.

    Substitute y = mx + c into the differential equation
    Substitute y = mx + c into the given differential equation (D^2 - 5D + 6)(mx + c) = x, and solve for m and c.

    Expand and simplify the equation
    Expanding and simplifying the equation, we get m(D^2 - 5D + 6) + c(D^2 - 5D + 6) = x.

    Collecting like terms
    Collecting like terms, we have (m + c)D^2 - 5m - 5c + 6c = x.

    Equating coefficients
    Equating the coefficients of x on both sides, we have 0 = 1, as there is no x term on the left-hand side.

    Find the value of c
    From the equation, we find that c = 0.138.
    Therefore, the value of c is 0.138.
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    The Particular Integral (PI) of the differential equation(D2– 5D+ 6)y=xis given asy=mx+c.Find the value ofc.Correct answer is '0.138'. Can you explain this answer?
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