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Common Data for Questions
Radiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.
Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.
Radiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.
Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.
Q. The irradiation (in kW/m2) for the upper plate (plate 1) is:
- a)2.5
- b)3.6
- c)17.0
- d)19.5
Correct answer is option 'D'. Can you explain this answer?
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Common Data for QuestionsRadiative heat transfer is intended between t...
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Common Data for QuestionsRadiative heat transfer is intended between t...
Given Data:
- Temperature of plate 1 (T1) = 727°C = 1000 K
- Temperature of plate 2 (T2) = 227°C = 500 K
- Emissivity of plate 2 (ε2) = 0.7
- Stefan-Boltzmann constant (σ) = 5.67 * 10^-8 W/m^2K^4
Assumptions:
- The surfaces of the plates are sufficiently large to form a two-surface enclosure.
- Steady-state conditions exist.
Explanation:
Radiative heat transfer between two surfaces can be calculated using the Stefan-Boltzmann law, which states that the net heat transfer between two surfaces is proportional to the difference in their temperatures raised to the fourth power.
Calculating Irradiation:
Irradiation is defined as the amount of radiant energy incident on a unit area of a surface. In this case, we need to calculate the irradiation for plate 1.
The irradiation for plate 1 can be calculated using the following formula:
I1 = σ * ε1 * (T1^4 - T2^4)
Here, ε1 is the emissivity of plate 1. Since plate 1 is a black surface, its emissivity is assumed to be 1.
Substituting the given values into the formula, we have:
I1 = 5.67 * 10^-8 * 1 * (1000^4 - 500^4)
I1 = 5.67 * 10^-8 * (10^12 - 10^8)
I1 = 5.67 * 10^-8 * (999,999,999,999,900)
Simplifying the Calculation:
To simplify the calculation, we can approximate 999,999,999,999,900 as 10^15.
I1 ≈ 5.67 * 10^-8 * 10^15
I1 ≈ 5.67 * 10^7
Converting to kW/m2:
Since the unit of irradiation is W/m2, we need to convert the value to kW/m2. To do this, we divide the value by 1000.
I1 ≈ 5.67 * 10^7 / 1000
I1 ≈ 5.67 * 10^4 kW/m2
Final Answer:
Therefore, the irradiation for the upper plate (plate 1) is approximately 5.67 * 10^4 kW/m2.
Correct Option:
The correct answer is option 'D'.
- Temperature of plate 1 (T1) = 727°C = 1000 K
- Temperature of plate 2 (T2) = 227°C = 500 K
- Emissivity of plate 2 (ε2) = 0.7
- Stefan-Boltzmann constant (σ) = 5.67 * 10^-8 W/m^2K^4
Assumptions:
- The surfaces of the plates are sufficiently large to form a two-surface enclosure.
- Steady-state conditions exist.
Explanation:
Radiative heat transfer between two surfaces can be calculated using the Stefan-Boltzmann law, which states that the net heat transfer between two surfaces is proportional to the difference in their temperatures raised to the fourth power.
Calculating Irradiation:
Irradiation is defined as the amount of radiant energy incident on a unit area of a surface. In this case, we need to calculate the irradiation for plate 1.
The irradiation for plate 1 can be calculated using the following formula:
I1 = σ * ε1 * (T1^4 - T2^4)
Here, ε1 is the emissivity of plate 1. Since plate 1 is a black surface, its emissivity is assumed to be 1.
Substituting the given values into the formula, we have:
I1 = 5.67 * 10^-8 * 1 * (1000^4 - 500^4)
I1 = 5.67 * 10^-8 * (10^12 - 10^8)
I1 = 5.67 * 10^-8 * (999,999,999,999,900)
Simplifying the Calculation:
To simplify the calculation, we can approximate 999,999,999,999,900 as 10^15.
I1 ≈ 5.67 * 10^-8 * 10^15
I1 ≈ 5.67 * 10^7
Converting to kW/m2:
Since the unit of irradiation is W/m2, we need to convert the value to kW/m2. To do this, we divide the value by 1000.
I1 ≈ 5.67 * 10^7 / 1000
I1 ≈ 5.67 * 10^4 kW/m2
Final Answer:
Therefore, the irradiation for the upper plate (plate 1) is approximately 5.67 * 10^4 kW/m2.
Correct Option:
The correct answer is option 'D'.
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Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer?
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Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer?.
Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer?.
Solutions for Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Common Data for QuestionsRadiative heat transfer is intended between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C.Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10-8 W/m2K4.Q.The irradiation (in kW/m2) for the upper plate (plate 1) is:a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
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