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Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.
The irradiation (in kW/m2) for the plate (plate 1) is
[2009]
  • a)
    2.5
  • b)
    3.6
  • c)
    17.0
  • d)
    19.5
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Radiative heat transfer is intercepted between the inner surfaces of t...
T1 = 1000 K
T2 = 500 K
∈ = 0.7

Energy indicent upon plate 1 due to irradiation = Radiosity of plate 2

σ (1- α) Eb1 = Fraction of energy reflected from surface 2
= (1 – 0.7) × 5.67 × 10–8 ×10004
 = 17010(W/m2)
∴ Total energy incident upon plate 1 = 
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Most Upvoted Answer
Radiative heat transfer is intercepted between the inner surfaces of t...
°C, the lower plate (designated as plate 2) is a gray surface and is maintained at 427°C. The emissivity of plate 1 is 0.8, and the emissivity of plate 2 is 0.4. The distance between the two plates is 2 mm.

To determine the radiative heat transfer between the two plates, we can use the Stefan-Boltzmann law, which states that the rate of radiative heat transfer between two surfaces is proportional to the fourth power of the absolute temperature difference and the product of the emissivities of the two surfaces. Mathematically, the law can be expressed as:

Q = σε1ε2A(T1^4 - T2^4)

where Q is the radiative heat transfer rate, σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4), ε1 and ε2 are the emissivities of plate 1 and plate 2, respectively, A is the surface area of the plates, T1 and T2 are the absolute temperatures of plate 1 and plate 2, respectively.

Substituting the given values, we get:

Q = (5.67 x 10^-8) x 0.8 x 0.4 x (0.02 x 0.02) x ((1000 + 727)^4 - (1000 + 427)^4)

Q = 331.4 W/m^2

Therefore, the radiative heat transfer between the two plates is 331.4 W/m^2.
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Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.The irradiation (in kW/m2) for the plate (plate 1) is[2009]a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer?
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Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.The irradiation (in kW/m2) for the plate (plate 1) is[2009]a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.The irradiation (in kW/m2) for the plate (plate 1) is[2009]a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.The irradiation (in kW/m2) for the plate (plate 1) is[2009]a)2.5b)3.6c)17.0d)19.5Correct answer is option 'D'. Can you explain this answer?.
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