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Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.
If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is
[2009]
- a)17.0
- b)19.5
- c)23.0
- d)31.7
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Radiative heat transfer is intercepted between the inner surfaces of t...
= 0.59
∴
= 0.59 x 5.67 x (10000 - 625)
= 31362.18 W/m2
= 31.36 kW/m2
Alternately
Net heat exchange between A and B,
Most Upvoted Answer
Radiative heat transfer is intercepted between the inner surfaces of t...
°C, the lower plate (designated as plate 2) is a gray surface and is the cooler one being maintained at 427°C. The emissivity of the black surface plate 1 is 0.95, while the emissivity of the gray surface plate 2 is 0.7.
To calculate the net radiative heat transfer between the two plates, we can use the Stefan-Boltzmann law, which states that the radiative heat transfer rate between two surfaces is proportional to the product of the emissivities and the fourth power of the absolute temperature difference.
The formula for radiative heat transfer rate is:
Q = ε₁ * ε₂ * σ * A * (T₁⁴ - T₂⁴)
Where:
Q = Net radiative heat transfer rate (W)
ε₁ = Emissivity of plate 1
ε₂ = Emissivity of plate 2
σ = Stefan-Boltzmann constant (5.67 × 10⁻⁸ W/m²K⁴)
A = Area of the plates (m²)
T₁ = Temperature of plate 1 (K)
T₂ = Temperature of plate 2 (K)
First, we need to convert the temperatures from Celsius to Kelvin:
T₁ = 727 + 273 = 1000 K
T₂ = 427 + 273 = 700 K
Given:
ε₁ = 0.95
ε₂ = 0.7
σ = 5.67 × 10⁻⁸ W/m²K⁴
Let's assume the plates have an area of 1 m²:
A = 1 m²
Plugging in these values into the formula, we can calculate the net radiative heat transfer rate:
Q = 0.95 * 0.7 * (5.67 × 10⁻⁸) * 1 * (1000⁴ - 700⁴)
Calculating this expression will give us the net radiative heat transfer rate between the two plates.
To calculate the net radiative heat transfer between the two plates, we can use the Stefan-Boltzmann law, which states that the radiative heat transfer rate between two surfaces is proportional to the product of the emissivities and the fourth power of the absolute temperature difference.
The formula for radiative heat transfer rate is:
Q = ε₁ * ε₂ * σ * A * (T₁⁴ - T₂⁴)
Where:
Q = Net radiative heat transfer rate (W)
ε₁ = Emissivity of plate 1
ε₂ = Emissivity of plate 2
σ = Stefan-Boltzmann constant (5.67 × 10⁻⁸ W/m²K⁴)
A = Area of the plates (m²)
T₁ = Temperature of plate 1 (K)
T₂ = Temperature of plate 2 (K)
First, we need to convert the temperatures from Celsius to Kelvin:
T₁ = 727 + 273 = 1000 K
T₂ = 427 + 273 = 700 K
Given:
ε₁ = 0.95
ε₂ = 0.7
σ = 5.67 × 10⁻⁸ W/m²K⁴
Let's assume the plates have an area of 1 m²:
A = 1 m²
Plugging in these values into the formula, we can calculate the net radiative heat transfer rate:
Q = 0.95 * 0.7 * (5.67 × 10⁻⁸) * 1 * (1000⁴ - 700⁴)
Calculating this expression will give us the net radiative heat transfer rate between the two plates.
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Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer?
Question Description
Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer?.
Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer?.
Solutions for Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
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Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Radiative heat transfer is intercepted between the inner surfaces of two very large isothermal parallel metal plates. While the upper plate (designated as plate 1) is a black surface and is the warmer one being maintained at 727°C, the lower plate (plate 2) is a diffuse and gray surface with an emissivity of 0.7 and is kept at 227°C. Assume that the surfaces are sufficiently large to form a two-surface enclosure and steady-state conditions to exist. Stefan-Boltzmann constant is given as 5.67 × 10–8 W/m2K4.If plate 1 is also a diffuse and gray surface with an emissivity value of 0.8, the net radiatibn heat exchange (in kW/m2) between plate 1 and plate 2 is[2009]a)17.0b)19.5c)23.0d)31.7Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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