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The probability that there is at least one error in an account statement prepared by 3 persons a b c are 0.2 , 0.3 and 0.1 respectively if A and B and C prepare 60 70 90 such statement then Expected number of correct statement?
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The probability that there is at least one error in an account stateme...
1)4*3/10 = 1.2
2)(60*0.8)+(70*0.7)+(90*0.9)=178
3) {(0.6+0.56)*20 + (0.6+0.44)*30 + (0.4+0.33)*40 + (0.4+0.67)*30} / 4
=(23.2 + 31.2 + 29.2 + 32.1) / 4
=28.9

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The probability that there is at least one error in an account stateme...
Expected Number of Correct Statements

To find the expected number of correct statements, we need to calculate the probability of each person making an error and use it to calculate the expected number of correct statements for each person.

Probability of Error for each person:
- Person A: The probability of A making an error is 0.2.
- Person B: The probability of B making an error is 0.3.
- Person C: The probability of C making an error is 0.1.

Expected Number of Correct Statements for each person:
- Person A: The expected number of correct statements for person A can be calculated by subtracting the probability of error (0.2) from 1 and then multiplying it by the total number of statements prepared by A (60).
Expected number of correct statements for A = (1 - 0.2) * 60 = 0.8 * 60 = 48.

- Person B: The expected number of correct statements for person B can be calculated in the same way.
Expected number of correct statements for B = (1 - 0.3) * 70 = 0.7 * 70 = 49.

- Person C: The expected number of correct statements for person C can be calculated in the same way.
Expected number of correct statements for C = (1 - 0.1) * 90 = 0.9 * 90 = 81.

Total Expected Number of Correct Statements:
To find the total expected number of correct statements, we need to sum up the expected number of correct statements for each person.
Total expected number of correct statements = Expected number of correct statements for A + Expected number of correct statements for B + Expected number of correct statements for C
Total expected number of correct statements = 48 + 49 + 81 = 178.

Therefore, the expected number of correct statements is 178.
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The probability that there is at least one error in an account statement prepared by 3 persons a b c are 0.2 , 0.3 and 0.1 respectively if A and B and C prepare 60 70 90 such statement then Expected number of correct statement?
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The probability that there is at least one error in an account statement prepared by 3 persons a b c are 0.2 , 0.3 and 0.1 respectively if A and B and C prepare 60 70 90 such statement then Expected number of correct statement? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The probability that there is at least one error in an account statement prepared by 3 persons a b c are 0.2 , 0.3 and 0.1 respectively if A and B and C prepare 60 70 90 such statement then Expected number of correct statement? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability that there is at least one error in an account statement prepared by 3 persons a b c are 0.2 , 0.3 and 0.1 respectively if A and B and C prepare 60 70 90 such statement then Expected number of correct statement?.
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