Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > Determine the complex power for hte given val...
Start Learning for Free
Determine the complex power for hte given values in question.
P = 269 W, Q = 150 VAR (capacitive)
- a)150 - j269 VA
- b)150 + j269 VA
- c)269 - j150 VA
- d)269 + j150 VA
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Determine the complex power for hte given values in question.P =269 W,...
S = P-jQ = 269-j150 VA
Most Upvoted Answer
Determine the complex power for hte given values in question.P =269 W,...
Understanding Complex Power
Complex power (S) is a combination of real power (P) and reactive power (Q) in an electrical system. It is represented as:
S = P + jQ
Where:
- P = Real power (in watts, W)
- Q = Reactive power (in volt-amperes reactive, VAR)
- j = Imaginary unit
Given Values
- Real Power (P) = 269 W
- Reactive Power (Q) = 150 VAR (capacitive)
Since the reactive power is capacitive, it will have a negative j component when represented in complex power notation:
- Q = -150 VAR
Calculating Complex Power
Using the formula for complex power:
S = P + jQ
Substituting the values:
S = 269 W - j150 VAR
This can be rewritten as:
S = 269 - j150 VA
Identifying the Correct Option
Reviewing the options given:
a) 150 - j269 VA
b) 150 + j269 VA
c) 269 - j150 VA
d) 269 + j150 VA
The calculated complex power, S = 269 - j150 VA, matches option c.
Conclusion
The correct answer is option 'C' because it accurately represents the real and reactive power values in the complex power format, confirming the relationship between P and Q in a capacitive system.
Complex power (S) is a combination of real power (P) and reactive power (Q) in an electrical system. It is represented as:
S = P + jQ
Where:
- P = Real power (in watts, W)
- Q = Reactive power (in volt-amperes reactive, VAR)
- j = Imaginary unit
Given Values
- Real Power (P) = 269 W
- Reactive Power (Q) = 150 VAR (capacitive)
Since the reactive power is capacitive, it will have a negative j component when represented in complex power notation:
- Q = -150 VAR
Calculating Complex Power
Using the formula for complex power:
S = P + jQ
Substituting the values:
S = 269 W - j150 VAR
This can be rewritten as:
S = 269 - j150 VA
Identifying the Correct Option
Reviewing the options given:
a) 150 - j269 VA
b) 150 + j269 VA
c) 269 - j150 VA
d) 269 + j150 VA
The calculated complex power, S = 269 - j150 VA, matches option c.
Conclusion
The correct answer is option 'C' because it accurately represents the real and reactive power values in the complex power format, confirming the relationship between P and Q in a capacitive system.
Attention Electronics and Communication Engineering (ECE) Students!
To make sure you are not studying endlessly, EduRev has designed Electronics and Communication Engineering (ECE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electronics and Communication Engineering (ECE).
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Similar Electronics and Communication Engineering (ECE) Doubts
Top Courses for Electronics and Communication Engineering (ECE)View all
Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer?
Question Description
Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer?.
Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer?.
Solutions for Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Determine the complex power for hte given values in question.P =269 W, Q =150 VAR (capacitive)a)150 -j269 VAb)150 +j269 VAc)269 -j150 VAd)269 +j150 VACorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
|
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x
![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup