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Let A be a 3 x 3 matrix with eigenvalues 1, —1,0. Then the determinant of I + A100 is
  • a)
    6
  • b)
    4
  • c)
    9
  • d)
    100
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let A be a 3 x 3 matrix with eigenvalues 1, —1,0. Then the deter...
Eigenvalues of (I + A100) is 1 + λ100
i e . l + 1 , 1 + 1,0 + 1
i.e.2,2,1
So, determinant of I + A100 is product of eigenvalues i. e. 4
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Most Upvoted Answer
Let A be a 3 x 3 matrix with eigenvalues 1, —1,0. Then the deter...
2, and 3. The determinant of A is the product of its eigenvalues, so the determinant of A is 1 * 2 * 3 = 6.
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Let A be a 3 x 3 matrix with eigenvalues 1, —1,0. Then the determinant of I + A100 isa)6b)4c)9d)100Correct answer is option 'B'. Can you explain this answer?
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