Solution:

Given information:
- The box contains a total of Rs 56 worth of coins.
- The coins in the box are of three denominations: 1 rupee, 50 paisa, and 25 paisa.
- The number of 50 paisa coins is twice the number of 25 paisa coins.
- The number of 50 paisa coins is 4 times the number of 1 rupee coins.

Let's solve this problem step by step.

Step 1: Assign variables to unknown quantities.
Let's assume the number of 1 rupee coins to be 'x'.
Then, the number of 50 paisa coins would be '4x' (four times the number of 1 rupee coins).
And the number of 25 paisa coins would be '2x' (twice the number of 1 rupee coins).

Step 2: Calculate the total value of the coins.
The value of 1 rupee coin = Rs 1
The value of 50 paisa coin = Rs 0.50
The value of 25 paisa coin = Rs 0.25

Using these values, we can calculate the total value of the coins in the box:
Total value = (Value of 1 rupee coin * Number of 1 rupee coins) + (Value of 50 paisa coin * Number of 50 paisa coins) + (Value of 25 paisa coin * Number of 25 paisa coins)

Total value = (1 * x) + (0.50 * 4x) + (0.25 * 2x)
Total value = x + 2x + 2x
Total value = 5x

Step 3: Solve for 'x'.
From the given information, the total value of the coins in the box is Rs 56.
So, we can equate the total value to Rs 56 and solve for 'x':
5x = 56
x = 56/5
x = 11.2

Since the number of coins cannot be in decimal form, we need to round off 'x' to the nearest whole number. Therefore, the number of 1 rupee coins is 11.

Step 4: Calculate the number of 50 paisa coins.
We know that the number of 50 paisa coins is 4 times the number of 1 rupee coins.
So, the number of 50 paisa coins = 4 * 11 = 44.

Therefore, the number of 50 paisa coins in the box is 44.

In conclusion, the box contains 44 fifty paisa coins.