Which of the following does not obey pumping lemma for context free la...
Explanation:
The pumping lemma for context-free languages states that if a language L is context-free, then there exists a pumping length p such that any string s in L with length greater than or equal to p can be divided into five parts u, v, x, y, and z, satisfying the following conditions:
- For all i ≥ 0, u(v^i)x(y^i)z is in L.
- The length of v and y combined is greater than 0.
- The length of vxy is less than or equal to p.
Finite languages:
A finite language is a language that contains a finite number of strings. Since finite languages have a finite number of strings, the pumping lemma does not apply to them. Therefore, finite languages do not need to obey the pumping lemma for context-free languages.
Context-free languages:
Context-free languages are a class of formal languages that can be generated by a context-free grammar. The pumping lemma applies to context-free languages, and if a language is context-free, it must obey the pumping lemma.
Unrestricted languages:
An unrestricted language is a language that can be generated by a type-0 grammar, also known as a recursively enumerable grammar. The pumping lemma for context-free languages does not apply to unrestricted languages because the pumping lemma is specifically designed for context-free languages.
Conclusion:
Out of the options given, the only one that does not obey the pumping lemma for context-free languages is unrestricted languages (option C). The pumping lemma applies to context-free languages, but unrestricted languages, which are a more general class of languages, do not necessarily need to obey the pumping lemma.