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For an opaque plane surface the irradiation, radiosity and emissive power are respectively 20, 12 and 10 W/m2.What is the emissivity of the surface?
- a)0.2
- b)0.4
- c)0.8
- d)1.0
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
For an opaque plane surface the irradiation, radiosity and emissive po...
Ans. (c)
J = ε Eb + (1 − ε) G
12 = ε ×10 + (1 −ε ) × 20 or ε = 0.8
J = ε Eb + (1 − ε) G
12 = ε ×10 + (1 −ε ) × 20 or ε = 0.8
Most Upvoted Answer
For an opaque plane surface the irradiation, radiosity and emissive po...
Given:
Irradiation = 20 W/m²
Radiosity = 12 W/m²
Emissive Power = 10 W/m²
To find: Emissivity of the surface
Formula used:
Emissivity (ε) = Emissive power (P) / Irradiation (I)
Calculation:
Substituting the given values in the formula,
ε = 10 / 20
ε = 0.5
Therefore, the emissivity of the surface is 0.5 or 50%.
Answer: Option (c) 0.8
Irradiation = 20 W/m²
Radiosity = 12 W/m²
Emissive Power = 10 W/m²
To find: Emissivity of the surface
Formula used:
Emissivity (ε) = Emissive power (P) / Irradiation (I)
Calculation:
Substituting the given values in the formula,
ε = 10 / 20
ε = 0.5
Therefore, the emissivity of the surface is 0.5 or 50%.
Answer: Option (c) 0.8
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Community Answer
For an opaque plane surface the irradiation, radiosity and emissive po...
J = E + Gref
J = E + rG
r=1-@(@->absorptivity)
considering kirchoff's law (@= e) (e=E/Eb) here and assuming conditions are satisfied to apply kirchoff's law or else we can't solve this.
J= E+ (1-e)G
12 = 10+ (1-e)20
2 = (1-e)20
0.1=1- e
e= 0.9
option C should be 0.9. This is the question from ESE 2004 please refer
J = E + rG
r=1-@(@->absorptivity)
considering kirchoff's law (@= e) (e=E/Eb) here and assuming conditions are satisfied to apply kirchoff's law or else we can't solve this.
J= E+ (1-e)G
12 = 10+ (1-e)20
2 = (1-e)20
0.1=1- e
e= 0.9
option C should be 0.9. This is the question from ESE 2004 please refer
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