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From a basket of mangoes when counted in twos there was one extra, when counted in threes there were two extra, when counted in fours there were three extra, when counted in fives there were four extra, when counted in sixes there were five extra . But when counted in sevens there no extra. Atleast how many mangoes were there in the basket?
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From a basket of mangoes when counted in twos there was one extra, whe...
Analysis of the Problem:
Given conditions:
- When counted in twos, there was one extra mango
- When counted in threes, there were two extra mangoes
- When counted in fours, there were three extra mangoes
- When counted in fives, there were four extra mangoes
- When counted in sixes, there were five extra mangoes
- When counted in sevens, there were no extra mangoes
Let's find the common multiple of 2, 3, 4, 5, and 6, and then add 1 to get the minimum number of mangoes in the basket.

Finding the Common Multiple:
The LCM of 2, 3, 4, 5, and 6 is 60.
Now, add 1 to the LCM to account for the extra mango when counted in twos:
60 + 1 = 61
Therefore, there are at least 61 mangoes in the basket to satisfy the given conditions.

Conclusion:
At least 61 mangoes were there in the basket to meet the conditions specified in the problem statement.
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From a basket of mangoes when counted in twos there was one extra, whe...
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From a basket of mangoes when counted in twos there was one extra, when counted in threes there were two extra, when counted in fours there were three extra, when counted in fives there were four extra, when counted in sixes there were five extra . But when counted in sevens there no extra. Atleast how many mangoes were there in the basket? Related: Math NCERT Solutions & NCERT Textbook of Class 6, CBSE?
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