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Type of isomerism exhibited by [Ir(OCN)2(H2O)3]
- a)Hydrate isomerism
- b)Linkage isomerism
- c)Polymerization isomerism
- d)Both (B) and (C)
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Type of isomerism exhibited by [Ir(OCN)2(H2O)3]a)Hydrate isomerismb)Li...
–OCN is ambident ligand & it shows linkage isomerism.
Most Upvoted Answer
Type of isomerism exhibited by [Ir(OCN)2(H2O)3]a)Hydrate isomerismb)Li...
Explanation:
The given complex is [Ir(OCN)2(H2O)3]. It has two isomers, i.e., linkage and polymerization isomers.
Linkage Isomerism:
In linkage isomerism, the ligand can coordinate through a different atom of the same ligand to form a different compound. Here, the OCN^- ion can coordinate via nitrogen (N) or carbon (C).
- If OCN^- binds through N atom, it forms a linkage isomer.
- If OCN^- binds through C atom, it forms a normal isomer.
Hence, [Ir(OCN-N)2(H2O)3] and [Ir(OCN-C)2(H2O)3] are linkage isomers.
Polymerization Isomerism:
In polymerization isomerism, the ligand can have different bridging modes between two metal centers. Here, the OCN^- ion can act as a bridging ligand to form a polymer chain.
- If OCN^- bridges between two Ir centers, it forms a polymerization isomer.
- If OCN^- binds to only one Ir center, it forms a normal isomer.
Hence, [Ir(OCN)2(H2O)3] and [Ir(OCN)2(μ-OCN)(H2O)2] are polymerization isomers.
Conclusion:
Thus, the given complex exhibits both linkage and polymerization isomerism.
The given complex is [Ir(OCN)2(H2O)3]. It has two isomers, i.e., linkage and polymerization isomers.
Linkage Isomerism:
In linkage isomerism, the ligand can coordinate through a different atom of the same ligand to form a different compound. Here, the OCN^- ion can coordinate via nitrogen (N) or carbon (C).
- If OCN^- binds through N atom, it forms a linkage isomer.
- If OCN^- binds through C atom, it forms a normal isomer.
Hence, [Ir(OCN-N)2(H2O)3] and [Ir(OCN-C)2(H2O)3] are linkage isomers.
Polymerization Isomerism:
In polymerization isomerism, the ligand can have different bridging modes between two metal centers. Here, the OCN^- ion can act as a bridging ligand to form a polymer chain.
- If OCN^- bridges between two Ir centers, it forms a polymerization isomer.
- If OCN^- binds to only one Ir center, it forms a normal isomer.
Hence, [Ir(OCN)2(H2O)3] and [Ir(OCN)2(μ-OCN)(H2O)2] are polymerization isomers.
Conclusion:
Thus, the given complex exhibits both linkage and polymerization isomerism.
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Type of isomerism exhibited by [Ir(OCN)2(H2O)3]a)Hydrate isomerismb)Linkage isomerismc)Polymerization isomerismd)Both (B) and (C)Correct answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Type of isomerism exhibited by [Ir(OCN)2(H2O)3]a)Hydrate isomerismb)Linkage isomerismc)Polymerization isomerismd)Both (B) and (C)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Type of isomerism exhibited by [Ir(OCN)2(H2O)3]a)Hydrate isomerismb)Linkage isomerismc)Polymerization isomerismd)Both (B) and (C)Correct answer is option 'D'. Can you explain this answer?.
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