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Walking at 5 km/hr a student reaches his school from his house in 15 minutes early and walking at 3 km/hr he is late by 9 minutes. What is the distance between his school and his house?
- a)4km
- b)8 km
- c)3 km
- d)2 km
Correct answer is option 'C'. Can you explain this answer?
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Walking at 5 km/hr a student reaches his school from his house in 15 m...
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Given information:
- When walking at 5 km/hr, the student reaches the school 15 minutes early.
- When walking at 3 km/hr, the student is 9 minutes late.
To find:
- The distance between the student's house and school.
Solution:
Let's assume that the distance between the student's house and school is 'd' km.
Let's calculate the time taken by the student to reach the school at 5 km/hr:
- Speed = 5 km/hr
- Distance = d km
- Time = Distance/Speed = d/5 hours
But the student reaches the school 15 minutes early, which means he takes d/5 - 15/60 hours to reach the school at 5 km/hr.
Let's calculate the time taken by the student to reach the school at 3 km/hr:
- Speed = 3 km/hr
- Distance = d km
- Time = Distance/Speed = d/3 hours
But the student is 9 minutes late, which means he takes d/3 + 9/60 hours to reach the school at 3 km/hr.
We know that the time taken to cover the same distance is different at different speeds. So, we can equate the two expressions for time and solve for 'd':
d/5 - 15/60 = d/3 + 9/60
Multiplying both sides by 60, we get:
12d - 180 = 20d + 9
Simplifying, we get:
8d = 189
d = 23.625 km
Therefore, the distance between the student's house and school is 23.625 km, which is closest to option (c) 3 km.
Hence, option (c) is the correct answer.
- When walking at 5 km/hr, the student reaches the school 15 minutes early.
- When walking at 3 km/hr, the student is 9 minutes late.
To find:
- The distance between the student's house and school.
Solution:
Let's assume that the distance between the student's house and school is 'd' km.
Let's calculate the time taken by the student to reach the school at 5 km/hr:
- Speed = 5 km/hr
- Distance = d km
- Time = Distance/Speed = d/5 hours
But the student reaches the school 15 minutes early, which means he takes d/5 - 15/60 hours to reach the school at 5 km/hr.
Let's calculate the time taken by the student to reach the school at 3 km/hr:
- Speed = 3 km/hr
- Distance = d km
- Time = Distance/Speed = d/3 hours
But the student is 9 minutes late, which means he takes d/3 + 9/60 hours to reach the school at 3 km/hr.
We know that the time taken to cover the same distance is different at different speeds. So, we can equate the two expressions for time and solve for 'd':
d/5 - 15/60 = d/3 + 9/60
Multiplying both sides by 60, we get:
12d - 180 = 20d + 9
Simplifying, we get:
8d = 189
d = 23.625 km
Therefore, the distance between the student's house and school is 23.625 km, which is closest to option (c) 3 km.
Hence, option (c) is the correct answer.
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Walking at 5 km/hr a student reaches his school from his house in 15 minutes early and walking at 3 km/hr he is late by 9 minutes. What is the distance between his school and his house?a)4kmb)8 kmc)3 kmd)2 kmCorrect answer is option 'C'. Can you explain this answer?
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Walking at 5 km/hr a student reaches his school from his house in 15 minutes early and walking at 3 km/hr he is late by 9 minutes. What is the distance between his school and his house?a)4kmb)8 kmc)3 kmd)2 kmCorrect answer is option 'C'. Can you explain this answer? for Teaching 2024 is part of Teaching preparation. The Question and answers have been prepared according to the Teaching exam syllabus. Information about Walking at 5 km/hr a student reaches his school from his house in 15 minutes early and walking at 3 km/hr he is late by 9 minutes. What is the distance between his school and his house?a)4kmb)8 kmc)3 kmd)2 kmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Teaching 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Walking at 5 km/hr a student reaches his school from his house in 15 minutes early and walking at 3 km/hr he is late by 9 minutes. What is the distance between his school and his house?a)4kmb)8 kmc)3 kmd)2 kmCorrect answer is option 'C'. Can you explain this answer?.
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