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Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.
- a)45 minutes
- b)50 minutes
- c)48 minutes
- d)60 minutes
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Walking from home at 2/3rd of his usual speed, a man reaches his offic...
If distance is constant then time taken in inversely proportional to the speed. When speed becomes two-third of the normal speed, time taken will be 3/2 times of his normal time. If the normal time to reach the office is T, then the man is taking T/2 time extra to reach the office.
If the man walk at 5/4 th of the normal speed, time taken will be 4/5 th of the normal time
If the man walk at 5/4 th of the normal speed, time taken will be 4/5 th of the normal time
Most Upvoted Answer
Walking from home at 2/3rd of his usual speed, a man reaches his offic...
Given information:
- The man reaches his office 30 minutes late when he walks at 2/3rd of his usual speed.
- We need to find the time taken by the man to reach his office when he walks at 5/4th of his usual speed.
Let's assume the man's usual speed is 'x' units of distance per unit of time.
Calculating the time taken when walking at 2/3rd speed:
- At 2/3rd speed, the man covers 2/3 * x units of distance per unit of time.
- Let's assume the distance between the man's home and office is 'd' units.
- So, the time taken to cover 'd' units of distance at 2/3rd speed is d / (2/3 * x) = 3d / (2x).
- The man reaches his office 30 minutes late, so the actual time taken is the calculated time + 30 minutes: 3d / (2x) + 30.
Calculating the time taken when walking at 5/4th speed:
- At 5/4th speed, the man covers 5/4 * x units of distance per unit of time.
- The time taken to cover 'd' units of distance at 5/4th speed is d / (5/4 * x) = 4d / (5x).
Equating the two times:
3d / (2x) + 30 = 4d / (5x)
Simplifying the equation:
15dx + 30(2x) = 8dx
15dx + 60x = 8dx
15dx - 8dx = -60x
7dx = -60x
7d = -60
d = -60 / 7
Since distance cannot be negative, the negative sign indicates that our assumption of the man's usual speed was incorrect. We need to reverse it.
Reversing the assumption:
- Let the man's usual speed be 'y' units of distance per unit of time.
- The distance between the man's home and office is 'd' units.
- The time taken to cover 'd' units of distance at y speed is d / y.
Calculating the time taken when walking at 2/3rd speed:
- At 2/3rd speed, the man covers 2/3 * y units of distance per unit of time.
- The time taken to cover 'd' units of distance at 2/3rd speed is d / (2/3 * y) = 3d / (2y).
- The man reaches his office 30 minutes late, so the actual time taken is the calculated time + 30 minutes: 3d / (2y) + 30.
Calculating the time taken when walking at 5/4th speed:
- At 5/4th speed, the man covers 5/4 * y units of distance per unit of time.
- The time taken to cover 'd' units of distance at 5/4th speed is d / (5/4 * y) = 4d / (5y).
Equating the two times:
3d / (2y) + 30 = 4d / (5y)
Simplifying the equation:
15dy + 30
- The man reaches his office 30 minutes late when he walks at 2/3rd of his usual speed.
- We need to find the time taken by the man to reach his office when he walks at 5/4th of his usual speed.
Let's assume the man's usual speed is 'x' units of distance per unit of time.
Calculating the time taken when walking at 2/3rd speed:
- At 2/3rd speed, the man covers 2/3 * x units of distance per unit of time.
- Let's assume the distance between the man's home and office is 'd' units.
- So, the time taken to cover 'd' units of distance at 2/3rd speed is d / (2/3 * x) = 3d / (2x).
- The man reaches his office 30 minutes late, so the actual time taken is the calculated time + 30 minutes: 3d / (2x) + 30.
Calculating the time taken when walking at 5/4th speed:
- At 5/4th speed, the man covers 5/4 * x units of distance per unit of time.
- The time taken to cover 'd' units of distance at 5/4th speed is d / (5/4 * x) = 4d / (5x).
Equating the two times:
3d / (2x) + 30 = 4d / (5x)
Simplifying the equation:
15dx + 30(2x) = 8dx
15dx + 60x = 8dx
15dx - 8dx = -60x
7dx = -60x
7d = -60
d = -60 / 7
Since distance cannot be negative, the negative sign indicates that our assumption of the man's usual speed was incorrect. We need to reverse it.
Reversing the assumption:
- Let the man's usual speed be 'y' units of distance per unit of time.
- The distance between the man's home and office is 'd' units.
- The time taken to cover 'd' units of distance at y speed is d / y.
Calculating the time taken when walking at 2/3rd speed:
- At 2/3rd speed, the man covers 2/3 * y units of distance per unit of time.
- The time taken to cover 'd' units of distance at 2/3rd speed is d / (2/3 * y) = 3d / (2y).
- The man reaches his office 30 minutes late, so the actual time taken is the calculated time + 30 minutes: 3d / (2y) + 30.
Calculating the time taken when walking at 5/4th speed:
- At 5/4th speed, the man covers 5/4 * y units of distance per unit of time.
- The time taken to cover 'd' units of distance at 5/4th speed is d / (5/4 * y) = 4d / (5y).
Equating the two times:
3d / (2y) + 30 = 4d / (5y)
Simplifying the equation:
15dy + 30
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Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer?
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Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer? for Teaching 2024 is part of Teaching preparation. The Question and answers have been prepared according to the Teaching exam syllabus. Information about Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Teaching 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer?.
Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer? for Teaching 2024 is part of Teaching preparation. The Question and answers have been prepared according to the Teaching exam syllabus. Information about Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Teaching 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer?.
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Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Walking from home at 2/3rd of his usual speed, a man reaches his office 30 minutes late. Had the person walked at 5/4th of his usual speed, find the time taken by the man to reach his office.a)45 minutesb)50 minutesc)48 minutesd)60 minutesCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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