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In an orthogonal machining with a single point cutting tool of rake angle 10o, the uncut chip
thickness and the chip thickness are 0.125 mm and 0.22 mm, respectively. Using Merchant’s
first solution for the condition of minimum cutting force, the coefficient of friction at the chip-tool
interface is ___________(round off to two decimal places).
    Correct answer is '0.74'. Can you explain this answer?
    Verified Answer
    In an orthogonal machining with a single point cutting tool of rake an...
    uncut chip thickness (t) = 0.125 mm
    Cut chip thickness (tc) = 0.22 mm
    So, ship thickness ratio
    Rake angle (α) = 10°

    Or shear angle (Ø) = 31.82°
    According to Merchant’s theory, we have

    So, β=90°−63.64+10=36.36°
    Now, tanβ=µ (coefficient of friction)
    Therefore, coefficient of friction = tan36.36°=0.74
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    Most Upvoted Answer
    In an orthogonal machining with a single point cutting tool of rake an...
    Circle analysis, determine the shear plane angle and the shear strain in the chip.

    Merchant circle analysis is a method used to analyze the forces and angles involved in orthogonal machining. It involves constructing a Merchant circle, which represents the cutting forces and their components.

    To determine the shear plane angle and shear strain, we can use the following equations derived from the Merchant circle analysis:

    T = Fc * tan(phi) / (1 - tan(phi) * tan(phi))
    tan(gamma) = tan(phi) / (1 - tan(phi) * tan(phi))

    where:
    T = shear plane angle
    gamma = shear strain
    Fc = cutting force
    phi = rake angle

    Given that the rake angle (phi) is 10 degrees, the uncut chip thickness (h0) is 0.125 mm, and the chip thickness (hc) is 0.22 mm, we can calculate the shear plane angle and shear strain.

    First, we need to calculate the cutting force (Fc) using the equation:

    Fc = (hc - h0) / tan(phi)

    Fc = (0.22 - 0.125) / tan(10) = 0.095 / 0.1763 = 0.539 N

    Now, we can substitute the values into the equations to find the shear plane angle (T) and shear strain (gamma):

    T = 0.539 * tan(10) / (1 - tan(10) * tan(10)) = 0.0955 radians

    gamma = tan(10) / (1 - tan(10) * tan(10)) = 0.0179

    Therefore, the shear plane angle is approximately 0.0955 radians and the shear strain is approximately 0.0179.
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    In an orthogonal machining with a single point cutting tool of rake angle 10o, the uncut chipthickness and the chip thickness are 0.125 mm and 0.22 mm, respectively. Using Merchant’sfirst solution for the condition of minimum cutting force, the coefficient of friction at the chip-toolinterface is ___________(round off to two decimal places).Correct answer is '0.74'. Can you explain this answer?
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    In an orthogonal machining with a single point cutting tool of rake angle 10o, the uncut chipthickness and the chip thickness are 0.125 mm and 0.22 mm, respectively. Using Merchant’sfirst solution for the condition of minimum cutting force, the coefficient of friction at the chip-toolinterface is ___________(round off to two decimal places).Correct answer is '0.74'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In an orthogonal machining with a single point cutting tool of rake angle 10o, the uncut chipthickness and the chip thickness are 0.125 mm and 0.22 mm, respectively. Using Merchant’sfirst solution for the condition of minimum cutting force, the coefficient of friction at the chip-toolinterface is ___________(round off to two decimal places).Correct answer is '0.74'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an orthogonal machining with a single point cutting tool of rake angle 10o, the uncut chipthickness and the chip thickness are 0.125 mm and 0.22 mm, respectively. Using Merchant’sfirst solution for the condition of minimum cutting force, the coefficient of friction at the chip-toolinterface is ___________(round off to two decimal places).Correct answer is '0.74'. Can you explain this answer?.
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