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Calculate the depression of melting point of ice (in K) produced by 1 atm increase of pressure, given that Lice = 80 cal gm-1 and specific volume of ice and water at 0°C are 1.091 cm3 and 1 cm3 respectively
Correct answer is '0.007429'. Can you explain this answer?
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Calculate the depression of melting point of ice (in K) produced by 1 ...
1 atm = 105 N/m2
= 106 dynes/cm2
The correct answer is: 0.007429
= 106 dynes/cm2
The correct answer is: 0.007429
Most Upvoted Answer
Calculate the depression of melting point of ice (in K) produced by 1 ...
To calculate the depression of the melting point of ice, we can use the Clausius-Clapeyron equation:
ΔT = (ΔH / TΔV) * P
Where:
ΔT = depression of melting point (in K)
ΔH = enthalpy of fusion of ice (in cal/g)
T = melting point of ice (in K)
ΔV = change in volume from ice to water (in cm³/g)
P = change in pressure (in atm)
Given:
ΔH = 80 cal/g
T = 0°C = 273.15 K
ΔV = specific volume of ice and water at 0°C (which is approximately 1 cm³/g at atmospheric pressure)
P = 1 atm
Substituting the given values into the formula, we have:
ΔT = (80 cal/g / (273.15 K * 1 cm³/g)) * 1 atm
Converting the units to the desired form:
ΔT = (80 cal/g / (273.15 K * 1 cm³/g)) * (1 atm * 1 cal / 4.184 J)
Simplifying the equation:
ΔT = 0.920 K
Therefore, the depression of the melting point of ice produced by a 1 atm increase in pressure is approximately 0.920 K.
ΔT = (ΔH / TΔV) * P
Where:
ΔT = depression of melting point (in K)
ΔH = enthalpy of fusion of ice (in cal/g)
T = melting point of ice (in K)
ΔV = change in volume from ice to water (in cm³/g)
P = change in pressure (in atm)
Given:
ΔH = 80 cal/g
T = 0°C = 273.15 K
ΔV = specific volume of ice and water at 0°C (which is approximately 1 cm³/g at atmospheric pressure)
P = 1 atm
Substituting the given values into the formula, we have:
ΔT = (80 cal/g / (273.15 K * 1 cm³/g)) * 1 atm
Converting the units to the desired form:
ΔT = (80 cal/g / (273.15 K * 1 cm³/g)) * (1 atm * 1 cal / 4.184 J)
Simplifying the equation:
ΔT = 0.920 K
Therefore, the depression of the melting point of ice produced by a 1 atm increase in pressure is approximately 0.920 K.
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Calculate the depression of melting point of ice (in K) produced by 1 atm increase of pressure, given that Lice = 80 cal gm-1 and specific volume of ice and water at 0°C are 1.091 cm3 and 1 cm3 respectivelyCorrect answer is '0.007429'. Can you explain this answer?
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Calculate the depression of melting point of ice (in K) produced by 1 atm increase of pressure, given that Lice = 80 cal gm-1 and specific volume of ice and water at 0°C are 1.091 cm3 and 1 cm3 respectivelyCorrect answer is '0.007429'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Calculate the depression of melting point of ice (in K) produced by 1 atm increase of pressure, given that Lice = 80 cal gm-1 and specific volume of ice and water at 0°C are 1.091 cm3 and 1 cm3 respectivelyCorrect answer is '0.007429'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the depression of melting point of ice (in K) produced by 1 atm increase of pressure, given that Lice = 80 cal gm-1 and specific volume of ice and water at 0°C are 1.091 cm3 and 1 cm3 respectivelyCorrect answer is '0.007429'. Can you explain this answer?.
Calculate the depression of melting point of ice (in K) produced by 1 atm increase of pressure, given that Lice = 80 cal gm-1 and specific volume of ice and water at 0°C are 1.091 cm3 and 1 cm3 respectivelyCorrect answer is '0.007429'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Calculate the depression of melting point of ice (in K) produced by 1 atm increase of pressure, given that Lice = 80 cal gm-1 and specific volume of ice and water at 0°C are 1.091 cm3 and 1 cm3 respectivelyCorrect answer is '0.007429'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the depression of melting point of ice (in K) produced by 1 atm increase of pressure, given that Lice = 80 cal gm-1 and specific volume of ice and water at 0°C are 1.091 cm3 and 1 cm3 respectivelyCorrect answer is '0.007429'. Can you explain this answer?.
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