The sum of the digits of two digit numbers is 10 . The tens digit of t...
The given problem states that the sum of the digits of a two-digit number is 10, and the tens digit is six more than the units digit. We need to find the number that satisfies these conditions.
To solve this problem, we can use algebraic expressions to represent the digits of the number. Let's assume that the units digit is x and the tens digit is y.
According to the problem, the sum of the digits is 10, so we can write the equation: x + y = 10.
We are also given that the tens digit is six more than the units digit, which can be expressed as: y = x + 6.
Now, we can solve these two equations simultaneously to find the values of x and y.
Solving the first equation for x, we get: x = 10 - y.
Substituting this value of x in the second equation, we have: y = (10 - y) + 6.
Simplifying this equation, we get: 2y = 16 - y.
Bringing y to one side, we have: 3y = 16.
Dividing both sides by 3, we find: y = 16/3.
However, since y represents the tens digit of a two-digit number, it must be a whole number. Therefore, y cannot be 16/3.
This means that there is no solution that satisfies the given conditions. Hence, there is no two-digit number where the sum of the digits is 10 and the tens digit is six more than the units digit.
Therefore, the correct answer is none of the options provided (d) 71.
The sum of the digits of two digit numbers is 10 . The tens digit of t...
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