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A transistor is connected in CB configuration. The emitter voltage is changed by 200mV, the emitter by 5mA. During this transition the collector base voltage is kept constant. What is the input dynamic resistance?
- a)30Ω
- b)60Ω
- c)40Ω
- d)50Ω
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A transistor is connected in CB configuration. The emitter voltage is ...
The ratio of change in emitter base voltage (∆VEB) to resulting change in emitter current (∆IE) at constant collector base voltage (VCB) is defined as input resistance. This is denoted by ri.
We know, ∆VEB/∆IE=ri
=200/5=40Ω.
We know, ∆VEB/∆IE=ri
=200/5=40Ω.
Most Upvoted Answer
A transistor is connected in CB configuration. The emitter voltage is ...
Explanation:
In a common base (CB) configuration of a transistor, the input is applied between the emitter and the base, and the output is taken between the collector and the base. The emitter current is the sum of the base current and the collector current.
Given:
Change in emitter voltage (ΔVE) = 200mV
Change in emitter current (ΔIE) = 5mA
Collector-base voltage (VCB) is constant.
Step 1: Determine the change in base current (ΔIB)
Since the collector-base voltage is constant, the collector current (IC) remains constant. Therefore, the change in emitter current is equal to the change in base current.
ΔIE = ΔIB
ΔIB = 5mA
Step 2: Calculate the input dynamic resistance (ri)
The input dynamic resistance (ri) is the ratio of the change in base voltage (ΔVB) to the change in base current (ΔIB).
ri = ΔVB / ΔIB
In a common base configuration, the base-emitter junction behaves like a diode, and the change in base voltage can be approximated to the change in emitter voltage.
ri = ΔVE / ΔIB
ri = 200mV / 5mA
ri = 40 Ω
Therefore, the input dynamic resistance is 40 Ω, which corresponds to option C.
In a common base (CB) configuration of a transistor, the input is applied between the emitter and the base, and the output is taken between the collector and the base. The emitter current is the sum of the base current and the collector current.
Given:
Change in emitter voltage (ΔVE) = 200mV
Change in emitter current (ΔIE) = 5mA
Collector-base voltage (VCB) is constant.
Step 1: Determine the change in base current (ΔIB)
Since the collector-base voltage is constant, the collector current (IC) remains constant. Therefore, the change in emitter current is equal to the change in base current.
ΔIE = ΔIB
ΔIB = 5mA
Step 2: Calculate the input dynamic resistance (ri)
The input dynamic resistance (ri) is the ratio of the change in base voltage (ΔVB) to the change in base current (ΔIB).
ri = ΔVB / ΔIB
In a common base configuration, the base-emitter junction behaves like a diode, and the change in base voltage can be approximated to the change in emitter voltage.
ri = ΔVE / ΔIB
ri = 200mV / 5mA
ri = 40 Ω
Therefore, the input dynamic resistance is 40 Ω, which corresponds to option C.
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A transistor is connected in CB configuration. The emitter voltage is changed by 200mV, the emitter by 5mA. During this transition the collector base voltage is kept constant. What is the input dynamic resistance?a)30Ωb)60Ωc)40Ωd)50ΩCorrect answer is option 'C'. Can you explain this answer?
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