For a perfect gas Joule - Thomson cofficient andmicro; is equal toSelect one:a)V 2/Rb)0c)1d)VCorrect answer is option 'B'. Can you explain this answer?

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For a perfect gas Joule - Thomson cofficient µ is equal to
Select one:

a)
V ²/R
b)
0
c)
1
d)
V

Correct answer is option 'B'. Can you explain this answer?

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Maxwell's Relations MCQ Level – 2

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For a perfect gas Joule - Thomson cofficient µ is equal toSelect...

Joule - Thomson coefficient µ,

For 1 mole of perfect gas, the equation of state is pV = RT
Differentiating it with respect to T, taking P constant,
We have,

Substituting this result in equation (1) we get,
Joule-Thomson coefficient, μ = 0
The correct answer is: 0

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