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A parallel-plate guide operates in the TEM mode only over the frequency range 0 < f < 3 GHz. The dielectric between the plates is teflon (εr = 2.1) .The maximum allowable plate separation b is
  • a)
    3.4 cm
  • b)
    6.8 cm
  • c)
    4.3 cm
  • d)
    8.6 cm
Correct answer is option 'A'. Can you explain this answer?
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Solution:

Given data:
Frequency range: 0< /><3>
Dielectric constant of Teflon: r=2.1

We know that a parallel-plate guide operates in the TEM mode only over the frequency range given by:

f

Where c is the speed of light in free space, b is the plate separation, and r is the relative dielectric constant of the dielectric between the plates.

To find the maximum allowable plate separation b, we can rearrange the above equation as:

b= (c/2f)√(1-1/r^2)

Substituting the given values, we get:

b= (3x10^8/2x3x10^9)√(1-1/2.1^2)
b= 3.4 cm

Therefore, the maximum allowable plate separation b is 3.4 cm, which is option (a).

Answer: The maximum allowable plate separation b is 3.4 cm.
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A parallel-plate guide operates in the TEM mode only over the frequenc...
Cut off frequency for parallel plate waveguide is c/ (2dsqrt(€r)). solve for d.
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A parallel-plate guide operates in the TEM mode only over the frequency range 0 < f < 3 GHz. The dielectric between the plates is teflon (εr= 2.1) .The maximum allowable plate separation b isa)3.4 cmb)6.8 cmc)4.3 cmd)8.6 cmCorrect answer is option 'A'. Can you explain this answer?
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