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0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample is
- a)80.0%
- b)90.0%
- c)95.0%
- d)75.0%
Correct answer is option 'B'. Can you explain this answer?
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0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with ...
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0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with ...
To find the percentage of CaSO4 present in the impure sample, we need to calculate the amount of CaSO4 in the sample and then determine the percentage.
Given data:
- Mass of impure CaSO4 = 0.400 g
- Molar mass of CaSO4 = 136 g/mol
- Mass of anhydrous BaSO4 formed = 0.617 g
- Molar mass of BaSO4 = 233 g/mol
Let's calculate the amount of CaSO4 in the impure sample:
- Molar ratio of CaSO4 to BaSO4 = 1:1 (from the balanced chemical equation)
- Moles of BaSO4 = Mass of BaSO4 / Molar mass of BaSO4
= 0.617 g / 233 g/mol
= 0.00265 mol
- Moles of CaSO4 = Moles of BaSO4
= 0.00265 mol
Now, let's calculate the percentage of CaSO4 in the impure sample:
- Mass of CaSO4 = Moles of CaSO4 * Molar mass of CaSO4
= 0.00265 mol * 136 g/mol
= 0.3604 g
Percentage of CaSO4 = (Mass of CaSO4 / Mass of impure sample) * 100
= (0.3604 g / 0.400 g) * 100
= 90.1%
Therefore, the percentage of CaSO4 present in the impure sample is approximately 90.1%.
Given data:
- Mass of impure CaSO4 = 0.400 g
- Molar mass of CaSO4 = 136 g/mol
- Mass of anhydrous BaSO4 formed = 0.617 g
- Molar mass of BaSO4 = 233 g/mol
Let's calculate the amount of CaSO4 in the impure sample:
- Molar ratio of CaSO4 to BaSO4 = 1:1 (from the balanced chemical equation)
- Moles of BaSO4 = Mass of BaSO4 / Molar mass of BaSO4
= 0.617 g / 233 g/mol
= 0.00265 mol
- Moles of CaSO4 = Moles of BaSO4
= 0.00265 mol
Now, let's calculate the percentage of CaSO4 in the impure sample:
- Mass of CaSO4 = Moles of CaSO4 * Molar mass of CaSO4
= 0.00265 mol * 136 g/mol
= 0.3604 g
Percentage of CaSO4 = (Mass of CaSO4 / Mass of impure sample) * 100
= (0.3604 g / 0.400 g) * 100
= 90.1%
Therefore, the percentage of CaSO4 present in the impure sample is approximately 90.1%.
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0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample isa)80.0%b)90.0%c)95.0%d)75.0%Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample isa)80.0%b)90.0%c)95.0%d)75.0%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample isa)80.0%b)90.0%c)95.0%d)75.0%Correct answer is option 'B'. Can you explain this answer?.
0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample isa)80.0%b)90.0%c)95.0%d)75.0%Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample isa)80.0%b)90.0%c)95.0%d)75.0%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.400 g of impure CaSO4 (Molar mass = 136) solution when treated with excess of barium chloride solution, gave 0.617 g of anhydrous BaSO4 (Molar mass = 233). The percentage of CaSO4 present in the sample isa)80.0%b)90.0%c)95.0%d)75.0%Correct answer is option 'B'. Can you explain this answer?.
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