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How many 3-letter words can be formed using the letters from the word GALE, if repetition is not allowed?
  • a)
    4
  • b)
    9
  • c)
    10
  • d)
    14
  • e)
    24
Correct answer is option 'E'. Can you explain this answer?
Verified Answer
How many 3-letter words can be formed using the letters from the word ...
Given: 4-letter word GALE
To find: Number of 3-letter words that can be formed without repeating any letters
Approach:
We will use the method of filling spaces to answer the question
Working Out:
  1. Let’s draw the 3 spaces, to denote the 3-letter word we need to form: _ _ _
  2. The objective of forming the word requires 3 tasks:
    1. Task 1 – Fill Space 1
    2. Task 2 – Fill Space 2
    3. Task 3 – Fill Space 3
  3. Since each of these 3 tasks need to be done to make the 3-letter word, we will multiply the number of ways to do each task:
  4. Number of ways to fill Space 1 = 4 (G, A, L, E – all letters are available at this point)
  5. Number of ways to fill Space 2 = 3
  6. Number of ways to fill Space 3 = 2
  7. So, (Number of 3-letter words) = 4*3*2 = 24
 
Answer: Option E
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This is a typical permutation-probability problem. To make this problem easily understandable we will break into two parts: i. First, we will find out all the seven lettered words from the letters of word CLASSIC ii. Next, we will find out how many of these words will have the two Cs together. The total number of words formed using the seven letters from the word CLASSIC is found by using the multiplication principle. There are seven places for each of the seven letters. The first place has 7 choices, the second place has (7-1) =6 choices, the third places has 5 choices and the seventh place has 1 choice. Hence, the total number of words formed is: = 7 x 6 x 5 x 4 x ... x 1 = 7! Notice that there are two Cs and two S in the word, which can be treated as repeated elements. To adjust for the repeated elements we will divide 7! by the product of 2! x 2! So, the total number of words formed is: 7!/(2! x 2!) We need to find how many of these words will have the two Cs together. To do this, let us treat the two Cs as a single entity. So, now we have six spaces to fill. Continuing the same way as in the step above, we can fill the first place in 6 ways, the second place in 5 ways and the sixth place in 1 way. Hence there are 6! ways of forming the words. Once again, we will need to adjust for the two S which can be done by dividing 6! by 2!. Total number of 7 lettered words such that the two Cs are always together = 6!/2! The fraction of seven lettered words such that the two Cs are always together is: = (number of words with two Cs together/total number of words) = (6!/2!)/(7!/[2! x 2!]) = (2!/7) = 2/7 Hence the correct answer choice is A.

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How many 3-letter words can be formed using the letters from the word GALE, if repetition is not allowed?a)4b)9c)10d)14e)24Correct answer is option 'E'. Can you explain this answer?
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How many 3-letter words can be formed using the letters from the word GALE, if repetition is not allowed?a)4b)9c)10d)14e)24Correct answer is option 'E'. Can you explain this answer? for GMAT 2024 is part of GMAT preparation. The Question and answers have been prepared according to the GMAT exam syllabus. Information about How many 3-letter words can be formed using the letters from the word GALE, if repetition is not allowed?a)4b)9c)10d)14e)24Correct answer is option 'E'. Can you explain this answer? covers all topics & solutions for GMAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many 3-letter words can be formed using the letters from the word GALE, if repetition is not allowed?a)4b)9c)10d)14e)24Correct answer is option 'E'. Can you explain this answer?.
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