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A triangle is to be constructed in the xy-plane such that the x- and y- coordinates of each vertex are integers that satisfy the inequalities -3 ≤ x < 7 and 2 < y ≤ 7. If one of the sides is parallel to the x-axis, how many different triangles with these specifications can be constructed?
  • a)
    18000
  • b)
    9000
  • c)
    1200
  • d)
    1008
  • e)
    504
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A triangle is to be constructed in the xy-plane such that the x- and y...
Given:
 
  • One side of the triangle is parallel to x – axis
  • The x- and y – coordinates of each vertex are integers.
  • For each vertex of the triangle,
    • -3 ≤ x < 7
    • 2 < y ≤ 7
To find: Number of different triangles that may be specified.
Approach:
  1. The objective here consists of the following tasks:
    • Task 1 – Choose the x-coordinates of the two vertices on the line parallel to x-axis
    • Task 2 – Chose x-coordinate of the 3rd point
    • Task 3 - Choose y-coordinate of the line parallel to x-axis
    • Task 4 – Choose y-coordinate of the third point

      Since each of these tasks must be performed in order to construct this triangle, the answer will be obtained by multiplying the number of ways of doing each task.
       
  2. Using the given inequalities and the fact that only integer values of x and y are allowed, we’ll find the number of ways of doing each task.

Working Out:
  • Choosing the x-coordinates of the 3 points
    • Finding number of ways to do Task 1:
      • -3 ≤ x < 7
      • That is, -3 ≤ x ≤ 6
      • Therefore, number of possible values of x is 10
      • So, ways to choose x-coordinates of the 2 vertices on the line parallel to x-axis =
 
  • Finding number of ways to do Task 2
    • Choices for third vertex’ x-coordinate = 10
      • (If the x-coordinate of the third vertex is the same as the x-coordinates of either of the two vertices that form the line parallel to x-axis, we get a right triangle)
  • Choosing the y-coordinates of the 3 points
    • Finding number of ways to do Task 3:
      • 2 < y ≤ 3
      • That is 3 ≤ y ≤ 7
      • So, number of possible values of y is 5
      • So, (Number of choices for y-coordinate of the line parallel to x-axis) = 5
  • Finding number of ways to do Task 4:
    • One of the 5 possible values of y is used up in Task 3
    • So, (Number of choices available for third vertex’ y-coordinate) = 4
  • Getting to the answer
    • So, total ways in which the triangle can be formed = 45*10*5*4 = 45*200  = 9000
 
Looking at the answer choices, we see that the correct answer is Option B
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Most Upvoted Answer
A triangle is to be constructed in the xy-plane such that the x- and y...
Solution:
Given, a triangle is to be constructed in the xy-plane such that the x- and y- coordinates of each vertex are integers that satisfy the inequalities -3 x 7 and 2 y 7. Also, one of the sides is parallel to the x-axis.

Finding the range of possible coordinates:
To construct a triangle, we need three vertices. Let’s consider the first vertex, which can have any x-coordinate from -3 to 7 and any y-coordinate from 2 to 7. This gives us a total of (7 - (-3) + 1) * (7 - 2 + 1) = 11 * 6 = 66 possible coordinates for the first vertex.

For the second vertex, we can place it on the x-axis (since one of the sides is parallel to the x-axis). If the first vertex has y-coordinate y1, then the second vertex must have y-coordinate y2 = y1 or y2 = y1 + 1 (since the y-coordinates must be integers). So, there are at most two possible y-coordinates for the second vertex.

If the first vertex has x-coordinate x1, then the second vertex must have x-coordinate x2 such that |x2 - x1| < h,="" where="" h="" is="" the="" length="" of="" the="" horizontal="" side="" of="" the="" triangle.="" since="" the="" horizontal="" side="" is="" parallel="" to="" the="" x-axis,="" h="" is="" the="" difference="" between="" the="" x-coordinates="" of="" the="" first="" and="" second="" vertices.="" so,="" h="x2" -="" x1.="" therefore,="" the="" possible="" values="" of="" x2="" are="" x1="" +="" 1,="" x1="" +="" 2,="" …,="" x1="" +="" h="" -="" />

Now, we need to find the possible values of x2 for each possible value of x1. If x1 = -3, then h can be 1, 2, 3, 4, 5, or 6. If x1 = -2, then h can be 1, 2, 3, 4, 5, 6, or 7, but we need to exclude the case where h = 7 because that would make the triangle degenerate (i.e., it would be a straight line). Similarly, if x1 = -1, then h can be 1, 2, 3, 4, 5, or 6, but we need to exclude the case where h = 6. For x1 = 0, 1, 2, 3, 4, 5, 6, we need to exclude the cases where h is equal to the length of the horizontal side of the triangle.

Counting the number of triangles:
For each possible pair of vertices (i.e., first and second vertices), we can count the number of possible third vertices. Since the third vertex cannot lie on the x-axis (otherwise, the triangle would be degenerate), the y-coordinate of the third vertex must be either y1 or y1 + 1 (depending on whether the second vertex has y-coordinate y1 or y1 + 1). If the second vertex has x-coordinate x2, then the possible x-coordinates of the third vertex are the integers between x1 and x2 that are not equal to x1 or x2. Therefore, the number of possible third vertices is (|x2 - x1| -
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A triangle is to be constructed in the xy-plane such that the x- and y- coordinates of each vertex are integers that satisfy the inequalities -3 ≤ x < 7 and 2 < y ≤ 7. If one of the sides is parallel to the x-axis, how many different triangles with these specifications can be constructed?a)18000b)9000c)1200d)1008e)504Correct answer is option 'B'. Can you explain this answer?
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