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Determine the minimum value of load resistance that can be used in the circuit with (IZ)Min=3mA. The input voltage is 10V and the resistance R is 500Ω. The Zener diode has a VZ=6V 0and (IZ)MAX=90mA.
  • a)
    1KΩ
  • b)
    2.4KΩ
  • c)
    1.2KΩ
  • d)
    3.6KΩ
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Determine the minimum value of load resistance that can be used in the...
The I=(VIN-VZ)/R=(10-6)/500=8mA. (IL)MAX=I-(IZ)MIN=8-3=5mA. (RL)MIN=VZ/(IL)MAX=6/5m=1.2KΩ.
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Most Upvoted Answer
Determine the minimum value of load resistance that can be used in the...
Given data:
IZ(min) = 3mA
Input voltage = 10V
Resistance R = 500Ω
VZ = 6V
IZ(max) = 90mA

To find: Minimum value of load resistance (RL) that can be used in the circuit

Concepts used:

- Zener diode
- Zener diode as voltage regulator
- Zener breakdown voltage
- Zener current

Explanation:

- In the given circuit, a Zener diode is used as a voltage regulator.
- A Zener diode operates in the breakdown region, where a small increase in voltage causes a large increase in current.
- The breakdown voltage of a Zener diode is denoted by VZ, which is the voltage at which the diode enters the breakdown region and maintains a constant voltage drop across it.
- The Zener current is the maximum current that can flow through the diode without damaging it.
- In the given circuit, the Zener diode is connected in reverse bias, so it allows only a small amount of current to flow through it until the breakdown voltage is reached.
- Once the breakdown voltage is reached, the Zener diode maintains a constant voltage of VZ across it, regardless of the current flowing through it.
- The current flowing through the load resistance RL is given by:

IZ = (Vin - VZ) / RL

- To find the minimum value of RL that can be used, we need to consider the minimum value of IZ, which is given as 3mA.
- Substituting the given values in the above equation, we get:

3mA = (10V - 6V) / RL

RL = (10V - 6V) / 3mA

RL = 1.2KΩ

- Therefore, the minimum value of load resistance that can be used in the circuit is 1.2KΩ.

Conclusion:

- The minimum value of load resistance that can be used in the circuit with IZ(min) = 3mA is 1.2KΩ.
- This value is obtained by using the equation IZ = (Vin - VZ) / RL and substituting the given values.
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Determine the minimum value of load resistance that can be used in the circuit with (IZ)Min=3mA. The input voltage is 10V and the resistance R is 500Ω. The Zener diode has a VZ=6V 0and (IZ)MAX=90mA.a)1KΩb)2.4KΩc)1.2KΩd)3.6KΩCorrect answer is option 'C'. Can you explain this answer?
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Determine the minimum value of load resistance that can be used in the circuit with (IZ)Min=3mA. The input voltage is 10V and the resistance R is 500Ω. The Zener diode has a VZ=6V 0and (IZ)MAX=90mA.a)1KΩb)2.4KΩc)1.2KΩd)3.6KΩCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Determine the minimum value of load resistance that can be used in the circuit with (IZ)Min=3mA. The input voltage is 10V and the resistance R is 500Ω. The Zener diode has a VZ=6V 0and (IZ)MAX=90mA.a)1KΩb)2.4KΩc)1.2KΩd)3.6KΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Determine the minimum value of load resistance that can be used in the circuit with (IZ)Min=3mA. The input voltage is 10V and the resistance R is 500Ω. The Zener diode has a VZ=6V 0and (IZ)MAX=90mA.a)1KΩb)2.4KΩc)1.2KΩd)3.6KΩCorrect answer is option 'C'. Can you explain this answer?.
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