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Extent of crystal field splitting in octahedral complexes of the given metal with particular weak field ligand are such that
  • a)
    Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)
  • b)
    Cr(iii) < Fe(iii) < Rh(iii) < Ir(iii)
  • c)
    Ir(iii) < Rh(iii) < Fe(iii) < Cr(iii)
  • d)
    Fe(iii) = Cr(iii) < Rh(iii) < Ir(iii)
Correct answer is option 'A'. Can you explain this answer?
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Extent of crystal field splitting in octahedral complexes of the given...
Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)
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Extent of crystal field splitting in octahedral complexes of the given...
To determine the extent of crystal field splitting in octahedral complexes of the given metals with a particular weak field ligand, we need to consider the electronic configurations and the nature of the metal ions.

a) Fe(iii), Cr(iii), Rh(iii), Ir(iii)

The electronic configurations of Fe(iii), Cr(iii), Rh(iii), and Ir(iii) are as follows:
- Fe(iii): [Ar] 3d^5
- Cr(iii): [Ar] 3d^3
- Rh(iii): [Kr] 4d^6
- Ir(iii): [Xe] 4f^14 5d^6

Fe(iii) has five d-electrons, which means it has a high-spin configuration. Cr(iii) has three d-electrons, which also results in a high-spin configuration. Rh(iii) and Ir(iii) have six d-electrons, which can accommodate low-spin configurations.

In an octahedral complex, the weak field ligand does not cause significant splitting of the d-orbitals. This is because the weak field ligand can only interact weakly with the metal ion, resulting in a small crystal field splitting.

The splitting of the d-orbitals in an octahedral complex is determined by the crystal field splitting parameter, Δo. In this case, since we have a weak field ligand, Δo will be small for all the given metals.

Therefore, the extent of crystal field splitting in octahedral complexes of Fe(iii), Cr(iii), Rh(iii), and Ir(iii) with a particular weak field ligand will be similar for all the metals. Hence, option 'A' is the correct answer.

In summary:
- The extent of crystal field splitting in octahedral complexes of Fe(iii), Cr(iii), Rh(iii), and Ir(iii) with a particular weak field ligand is similar for all the metals.
- The weak field ligand does not cause significant splitting of the d-orbitals in an octahedral complex.
- The electronic configurations of Fe(iii), Cr(iii), Rh(iii), and Ir(iii) determine the number of d-electrons and the possibility of high-spin or low-spin configurations.
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Read the passage given below and answer the following questions:The crystal field theory (CFT) is an electrostatic model which considers the metal-ligand bond to be ionic arising purely from electrostatic interactions between the metal ion and the ligand. Ligands are treated as point charges in case of anions or dipoles in case of neutral molecules. The five d orbitals in an isolated gaseous metal atom/ion have same energy, i.e., they are degenerate. This degeneracy is maintained if a spherically symmetrical field of negative charges surrounds the metal atom/ ion. However, when this negative field is due to ligands (either anions or the negative ends of dipolar molecules like NH3 and H2O) in a complex, it becomes asymmetrical and the degeneracy of the d orbitals is lifted. It results in splitting of the d orbitals.The following questions are multiple choice questions. Choose the most appropriate answer:Q. An aqueous pink solution of cobalt(II) chloride changes to deep blue on addition of excess of HCl. This is because _____________.

When a transition metal ion (usually) is involved in octahedral complex formation, the five degenerate d-orbitals split into two set of degenerate orbitals (3 + 2). Three degenerate orbitals of lower energy (dxy, dyz, dzx) and a set of degenerate orbitals of higher energy (dx2 y2and dz2). The orbitals with lower energy are called t2gorbitals and those with higher energy are called egorbitals.In octahedral complexes, positive metal ion may be considered to be present at the centre and negative ligands at the corner of a regular octahedron. As lobes ofandlie along the axes, i.e., along the ligands the repulsions are more and so high is the energy. The lobes of the remaining three d-orbitals lie between the axes. i.e., between the ligands. The repulsion between them are less, so lesser the energy. In the octahedral complexes, if metal ion has electrons more than 3 then for pairing them the option are(i) Pairing may start with 4thelectron in t2gorbitals.(ii) Pairing may start normally with 6thelectrons when t2gand egorbitals are singly filled.Q. Select incorrect match for the following complexes.

When a transition metal ion (usually) is involved in octahedral complex formation, the five degenerate d-orbitals split into two set of degenerate orbitals (3 + 2). Three degenerate orbitals of lower energy (dxy, dyz, dzx) and a set of degenerate orbitals of higher energy (dx2 y2and dz2). The orbitals with lower energy are called t2gorbitals and those with higher energy are called egorbitals.In octahedral complexes, positive metal ion may be considered to be present at the centre and negative ligands at the corner of a regular octahedron. As lobes ofandlie along the axes, i.e., along the ligands the repulsions are more and so high is the energy. The lobes of the remaining three d-orbitals lie between the axes. i.e., between the ligands. The repulsion between them are less, so lesser the energy. In the octahedral complexes, if metal ion has electrons more than 3 then for pairing them the option are(i) Pairing may start with 4thelectron in t2gorbitals.(ii) Pairing may start normally with 6thelectrons when t2gand egorbitals are singly filled.Q. Which of the following electronic arrangement is /are possible for inner orbital oct complex.(I)(II)(III)(IV)Select the correct code

Extent of crystal field splitting in octahedral complexes of the given metal with particular weak field ligand are such thata)Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)b)Cr(iii) < Fe(iii) < Rh(iii) < Ir(iii)c)Ir(iii) < Rh(iii) < Fe(iii) < Cr(iii)d)Fe(iii) = Cr(iii) < Rh(iii) < Ir(iii)Correct answer is option 'A'. Can you explain this answer?
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Extent of crystal field splitting in octahedral complexes of the given metal with particular weak field ligand are such thata)Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)b)Cr(iii) < Fe(iii) < Rh(iii) < Ir(iii)c)Ir(iii) < Rh(iii) < Fe(iii) < Cr(iii)d)Fe(iii) = Cr(iii) < Rh(iii) < Ir(iii)Correct answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Extent of crystal field splitting in octahedral complexes of the given metal with particular weak field ligand are such thata)Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)b)Cr(iii) < Fe(iii) < Rh(iii) < Ir(iii)c)Ir(iii) < Rh(iii) < Fe(iii) < Cr(iii)d)Fe(iii) = Cr(iii) < Rh(iii) < Ir(iii)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Extent of crystal field splitting in octahedral complexes of the given metal with particular weak field ligand are such thata)Fe(iii) < Cr(iii) < Rh(iii) < Ir(iii)b)Cr(iii) < Fe(iii) < Rh(iii) < Ir(iii)c)Ir(iii) < Rh(iii) < Fe(iii) < Cr(iii)d)Fe(iii) = Cr(iii) < Rh(iii) < Ir(iii)Correct answer is option 'A'. Can you explain this answer?.
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