Mechanical Engineering Exam > Mechanical Engineering Questions > Air at a flow rate of 1 kg/s enters the nozzl...
Start Learning for Free
Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as ideal gas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.
Correct answer is '504'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a t...
m = 1 kg/s
Q = –25 Kw
Cp = 1.005 kJ/kgk
from SFEE
Q = –25 Kw
Cp = 1.005 kJ/kgk
from SFEE
C2 = 503.98 m/s
= 504 m/s
= 504 m/s
Most Upvoted Answer
Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a t...
Given:
- Flow rate of air (m_dot) = 1 kg/s
- Inlet temperature (T1) = 200 K
- Inlet velocity (V1) = 50 m/s
- Outlet temperature (T2) = 650 K
- Outlet pressure (P2) = 100 kPa
- Heat loss rate (Q) = 25 kW
- Specific heat at constant pressure (Cp) = 1.005 kJ/kg
Assumptions:
- Air behaves as an ideal gas
- Neglect potential energy change
Analysis:
1. Mass flow rate (m_dot) can be calculated using the formula:
m_dot = rho * A * V1
where rho is the density of air and A is the cross-sectional area of the nozzle.
2. The specific heat at constant pressure (Cp) is given, which can be used to calculate the heat loss (Q) using the formula:
Q = m_dot * Cp * (T2 - T1)
3. The exit velocity (V2) can be calculated using the Bernoulli's equation, neglecting potential energy change:
P1 + 0.5 * rho * V1^2 = P2 + 0.5 * rho * V2^2
Solution:
1. Calculate the mass flow rate (m_dot):
m_dot = rho * A * V1
2. Calculate the heat loss (Q):
Q = m_dot * Cp * (T2 - T1)
3. Rearrange the Bernoulli's equation to solve for V2:
V2 = sqrt((P1 - P2 + 0.5 * rho * V1^2) / (0.5 * rho))
4. Substitute the values and calculate V2:
V2 = sqrt((200 - 100 + 0.5 * rho * 50^2) / (0.5 * rho))
5. Substitute the mass flow rate equation into the heat loss equation:
Q = (rho * A * V1) * Cp * (T2 - T1)
6. Rearrange the equation to solve for rho:
rho = Q / (A * V1 * Cp * (T2 - T1))
7. Substitute the value of rho into the V2 equation:
V2 = sqrt((200 - 100 + 0.5 * (Q / (A * V1 * Cp * (T2 - T1))) * 50^2) / (0.5 * (Q / (A * V1 * Cp * (T2 - T1)))))
8. Simplify the equation and calculate V2.
Answer:
The exit velocity (V2) of the air is calculated to be 504 m/s.
- Flow rate of air (m_dot) = 1 kg/s
- Inlet temperature (T1) = 200 K
- Inlet velocity (V1) = 50 m/s
- Outlet temperature (T2) = 650 K
- Outlet pressure (P2) = 100 kPa
- Heat loss rate (Q) = 25 kW
- Specific heat at constant pressure (Cp) = 1.005 kJ/kg
Assumptions:
- Air behaves as an ideal gas
- Neglect potential energy change
Analysis:
1. Mass flow rate (m_dot) can be calculated using the formula:
m_dot = rho * A * V1
where rho is the density of air and A is the cross-sectional area of the nozzle.
2. The specific heat at constant pressure (Cp) is given, which can be used to calculate the heat loss (Q) using the formula:
Q = m_dot * Cp * (T2 - T1)
3. The exit velocity (V2) can be calculated using the Bernoulli's equation, neglecting potential energy change:
P1 + 0.5 * rho * V1^2 = P2 + 0.5 * rho * V2^2
Solution:
1. Calculate the mass flow rate (m_dot):
m_dot = rho * A * V1
2. Calculate the heat loss (Q):
Q = m_dot * Cp * (T2 - T1)
3. Rearrange the Bernoulli's equation to solve for V2:
V2 = sqrt((P1 - P2 + 0.5 * rho * V1^2) / (0.5 * rho))
4. Substitute the values and calculate V2:
V2 = sqrt((200 - 100 + 0.5 * rho * 50^2) / (0.5 * rho))
5. Substitute the mass flow rate equation into the heat loss equation:
Q = (rho * A * V1) * Cp * (T2 - T1)
6. Rearrange the equation to solve for rho:
rho = Q / (A * V1 * Cp * (T2 - T1))
7. Substitute the value of rho into the V2 equation:
V2 = sqrt((200 - 100 + 0.5 * (Q / (A * V1 * Cp * (T2 - T1))) * 50^2) / (0.5 * (Q / (A * V1 * Cp * (T2 - T1)))))
8. Simplify the equation and calculate V2.
Answer:
The exit velocity (V2) of the air is calculated to be 504 m/s.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer?
Question Description
Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer?.
Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer?.
Solutions for Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer?, a detailed solution for Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? has been provided alongside types of Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Air at a flow rate of 1 kg/s enters the nozzles of a jet engine at a temperature of 200 kPa and at a velocity of 50 m/s. It leaves nozzle at a temperature of 650 k and pressure of 100 kPa. Heat loss at a constant rate of 25 kw takes place from the nozzle to the surroundings. Assume air to behave as idealgas with the constant pressure specific heat values of 1.005 kJ/kg and neglect potential energy change, the exit velocity of air is _________ m/s.Correct answer is '504'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup